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ArbitrLikvidat [17]
3 years ago
9

Find the isosceles triangle area

Mathematics
1 answer:
iVinArrow [24]3 years ago
4 0

Answer:

60 cm²

Step-by-step explanation:

base = 10

Height = √13² - 5² = √144 = 12

area = 1/2BH = 1/2 * 10 * 12 = 60

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Well I'm having troubles with something I have no idea what it is or how to do it. The problem is x^2 -18x+8=0. I only know how
Lubov Fominskaja [6]

Answer:

x = \frac{-(-18) -\sqrt{(-18)^2 -4*1*8}}{2} = \frac{18 -2 \sqrt{73}}{2}= 9 -\sqrt{73}

x = \frac{-(-18) +\sqrt{(-18)^2 -4*1*8}}{2} = \frac{18 +2 \sqrt{73}}{2}= 9 +\sqrt{73}

Step-by-step explanation:

We have the following equation:

x^2 -18 x +8 =0

We can use the quadratic formula given by:

x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}

Where:

a = 1 , b=-18, c =8

And replacing we got:

x = \frac{-(-18) -\sqrt{(-18)^2 -4*1*8}}{2} = \frac{18 -2 \sqrt{73}}{2}= 9 -\sqrt{73}

x = \frac{-(-18) +\sqrt{(-18)^2 -4*1*8}}{2} = \frac{18 +2 \sqrt{73}}{2}= 9 +\sqrt{73}

6 0
3 years ago
Please answer this question I give brainliest thank you! Number 16
lawyer [7]

Answer:

4a

Step-by-step explanation:

The mean is found by adding all of the data set together and then dividing by the amount of individual pieces of data in the set.

(2+3+3+8) = 16

16/4=4

The answer is 4a.

5 0
3 years ago
Lin’s bike travels 100 meters when her wheels rotate 55 times. What is the circumference of her wheels?
natka813 [3]

Answer:

<h2><em><u>the circumference of her wheel is 1.81 m </u></em></h2>

Lin’s bike travels 100 meters when her wheels rotate 55 times.

here, n = 55 rotation and D = 100 meter.

Diameter is the distance bike travel

n is the number of times rotation

C is the circumference of the wheel

6 0
3 years ago
What is the equation for the line in slope-intercept form?
iris [78.8K]

Answer:

y = mx+b

Step-by-step explanation:

This is the equation for finding the slope-intercept form. Just plug in the numbers and you'll get your answer.

I know this doesn't give you the exact answer, but you have to figure things out on your own. It's good to get a little help, but not the direct answer.

5 0
3 years ago
Container 1 has 8 items, 3 of which are defective. Container 2 has 5 items, 2 of which are defective. If one item is drawn from
e-lub [12.9K]

Answer:

The required probability is \frac{19}{40}

Step-by-step explanation:

The probability of obtaining a defective item from container 1 is P(E_1)=\frac{3}{8}

The probability of obtaining a good item from container 1 is P(E_1)=\frac{5}{8}

The probability of obtaining a defective item from container 2 is P(E_1)=\frac{2}{5}

The probability of obtaining a good item from container 2 is P(E_1)=\frac{3}{5}

The cases of the event are

1)Defective item is drawn from container 1 and good item is drawn from container 2

2)Defective item is drawn from container 2 and good item is drawn from container 1

Thus the required probability is the sum of above 2 cases

P(Event)=\frac{3}{8}\times \frac{3}{5}+\frac{5}{8}\times \frac{2}{5}=\frac{19}{40}

4 0
3 years ago
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