3 years ago

SOMEONE HELP ME PLEASE

Mathematics

1 answer:

jeyben [28]3 years ago

3 0

Answer:

$15,728.24 will be left in the account after 5 years.

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Suppose an architect draws a segment on a scale drawing with the end points (0,0) and (3⁄4,9⁄10). The same segment on the actual

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Segment drawn on scale having end points O (0,0) and A $(\frac{3}{4},\frac{9}{10})$ is a line segment.

O A= $\sqrt{[\frac{3}{4} -0]^{2} +[\frac{9}{10} -0]^{2}\\\\$

O A = $= \sqrt{\frac{9}{16}+\frac{81}{100}$

= $\sqrt\frac{549}{400}$

= $\frac{\sqrt{549}}{20}$

Now , the same segment actual structure having end points O'(0,0) and B (30,36) is also a line segment.

O'B= $\sqrt{(30-0)^{2}+(36-0)^{2}$

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= $\sqrt {2196}$

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$\frac{\text{Actual length}}{\text{Length on scale}}=\frac{OB'}{OA}=\frac{2\sqrt549}{\frac{\sqrt549}{20}}=40$ [Cancelling √549 from numerator and denominator]

So, Actual length = 40 × Length on scale

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3 years ago

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3 years ago

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