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3 years ago

Which car has the most kinetic energy?

Chemistry

1 answer:

luda_lava [24]3 years ago

7 0

Answer:

<h3>.A car of mass 1800kg with speed 15m/s</h3><h3>Opinion C</h3>

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The oxidation number of an atom is shown with a

Assoli18 [71]

Answer:

The oxidation number of an atom is the charge it appears to have when you count the electrons according to some arbitrary rules. The oxidation number of an atom depends on the other atoms in the substance.

Explanation:

For example, In KCl, the oxidation number of Cl is 0.

3 0

3 years ago

A photon has a wavelength of 3.8 x 10^-7 meters, what is the energy of this photon?

Korvikt [17]

Energy E = hc / l

where h = Planck's constant, c = speed of light and l = wavelength.

E = 1.986 * 10^-25 / 3.8 * 10^-7 = 5.223*10^-19

5 0

4 years ago

Read 2 more answers

1. Which groups of the periodic table constitute p-block?

DENIUS [597]

Groups 13 through 18 are the constitute p-block

8 0

3 years ago

The reaction of NH3 and O2 forms NO and water. The NO can be used to convert P4 to P4O6, forming N2 in the process. The P4O6 can

posledela

Answer : The mass of $PH_3$ produced from the reaction is, 0.651 grams.

Explanation :

The chemical reactions used are:

(1) $4NH_3+5O_2\rightarrow 4NO+6H_2O$

(2) $6NO+P_4\rightarrow P_4O_6+3N_2$

(3) $P_4O_6+6H_2O\rightarrow 4H_3PO_4$

(4) $4H_3PO_4\rightarrow PH_3+3H_3PO_4$

First we have to calculate the moles of $NH_3$

$\text{Moles of }NH_3=\frac{\text{Mass of }NH_3}{\text{Molar mass of }NH_3}$

Molar mass of $NH_3$ = 17 g/mol

$\text{Moles of }NH_3=\frac{1.95g}{17g/mol}=0.115mol$

Now we have to calculate the moles of $NO$

From the balanced chemical reaction 1, we conclude that:

As, 4 moles of $NH_3$ react to give 4 moles of $NO$

So, 0.115 moles of $NH_3$ react to give 0.115 moles of $NO$

Now we have to calculate the moles of $P_4O_6$

From the balanced chemical reaction 2, we conclude that:

As, 6 moles of $NO$ react to give 1 moles of $P_4O_6$

So, 0.115 moles of $NO$ react to give $\frac{0.115}{6}=0.0192$ moles of $P_4O_6$

Now we have to calculate the moles of $H_3PO_4$

From the balanced chemical reaction 3, we conclude that:

As, 1 moles of $P_4O_6$ react to give 4 moles of $H_3PO_4$

So, 0.0192 moles of $P_4O_6$ react to give $0.0192\times 4=0.0768$ moles of $H_3PO_4$

Now we have to calculate the moles of $PH_3$

From the balanced chemical reaction 4, we conclude that:

As, 4 moles of $H_3PO_4$ react to give 1 moles of $PH_3$

So, 0.0768 moles of $H_3PO_4$ react to give $\frac{0.0768}{4}=0.0192$ moles of $PH_3$

Now we have to calculate the mass of $PH_3$

$\text{ Mass of }PH_3=\text{ Moles of }PH_3\times \text{ Molar mass of }PH_3$

Molar mass of $PH_3$ = 33.9 g/mole

$\text{ Mass of }PH_3=(0.0192moles)\times (33.9g/mole)=0.651g$

Therefore, the mass of $PH_3$ produced from the reaction is, 0.651 grams.

6 0

3 years ago

What volume of water must be added

stellarik [79]

Answer:

litre.50000665432158900643212lo

3 0

3 years ago