Answer:The answer is 3...I think
Explanation:
143
Sig Figs
3
Decimals
0
Scientific Notation
1.43 × 102
The wheels will be completely used up and it is the limiting reactant in this case.
<h3>What is a limiting reactant?</h3>
The limiting reactant is the reactant that is completely used up in a reaction, and thus determines when the reaction stops.
- 60 breaks will be used for 30 engines and 30 body frame
- 80 wheels will be used for 20 engines and 20 body frame
- 64 headlights will be used for 32 engines and 32 body frame
The wheels will be completely used up and it is the limiting reactant in this case.
Learn more about limiting reactants here: brainly.com/question/14222359
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Answer:
8.8g of Al are necessaries
Explanation:
Based on the reaction, 2 moles of Al are required to produce 3 moles of hydrogen gas.
To solve this question we must find the moles of H2 in 11L at STP using PV = nRT. With these moles we can find the moles of Al required and its mass as follows:
<em>Moles H2:</em>
PV = nRT; PV/RT = n
<em>Where P is pressure = 1atm at STP; V is volume = 11L; R is gas constant = 0.082atmL/molK and T is absolute temperature = 273.15K at STP</em>
Replacing:
1atm*11L/0.082atmL/molK*273.15K = n
n = 0.491 moles of H2 must be produced
<em />
<em>Moles Al:</em>
0.491 moles of H2 * (2mol Al / 3mol H2) = 0.327moles of Al are required
<em />
<em>Mass Al -Molar mass: 26.98g/mol-:</em>
0.327moles of Al * (26.98g / mol) = 8.8g of Al are necessaries
You might have meant hemiacetal, not hemicetal.
Acetals contain two –OR groups, one –R group and a –H atom. In hemiacetals, one of the –OR groups in acetals is replaced by a –OH group<span>.
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