1.more
2.longer
3.warmer
4.northern
5.less
6.shorter
7.colder
8.southern
The fraction of the original amount remaining is closest to 1/128
<h3>Determination of the number of half-lives</h3>
- Half-life (t½) = 4 days
- Time (t) = 4 weeks = 4 × 7 = 28 days
- Number of half-lives (n) =?
n = t / t½
n = 28 / 4
n = 7
<h3>How to determine the amount remaining </h3>
- Original amount (N₀) = 100 g
- Number of half-lives (n) = 7
- Amount remaining (N)=?
N = N₀ / 2ⁿ
N = 100 / 2⁷
N = 0.78125 g
<h3>How to determine the fraction remaining </h3>
- Original amount (N₀) = 100 g
- Amount remaining (N)= 0.78125 g
Fraction remaining = N / N₀
Fraction remaining = 0.78125 / 100
Fraction remaining = 1/128
Learn more about half life:
brainly.com/question/26374513
Answer:
This is because no energy is being created or destroyed in this system
Explanation:
I think this is correct? I hope it helps.
Let the 8% solution be A, the 20% solution be B and the final solution be C.
C = A + B
C = 12 + B
0.16C = 0.08(12) + 0.2(B)
0.16(12 + B) = 0.96 + 0.2B
0.96 = 0.04B
B = 24 Liters
C = 12 + 24
C = 36 Liters
Answer:
The equilibrium concentration of HCl is 0.01707 M.
Explanation:
Equilibrium constant of the reaction = 
Moles of ammonium chloride = 0.573 mol
Concentration of ammonium chloride = 
Initial: 0.573 0 0
At eq'm: (0.573-x) x x
We are given:
![[NH_4Cl]_{eq}=(0.573-x)](https://tex.z-dn.net/?f=%5BNH_4Cl%5D_%7Beq%7D%3D%280.573-x%29)
![[HCl]_{eq}=x](https://tex.z-dn.net/?f=%5BHCl%5D_%7Beq%7D%3Dx)
![[NH_3]_{eq}=x](https://tex.z-dn.net/?f=%5BNH_3%5D_%7Beq%7D%3Dx)
Calculating for 'x'. we get:
The expression of 
for above reaction follows:
![K_c=\frac{[HCl][NH_3]}{[NH_4Cl]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BHCl%5D%5BNH_3%5D%7D%7B%5BNH_4Cl%5D%7D)
Putting values in above equation, we get:
On solving this quadratic equation we get:
x = 0.01707 M
The equilibrium concentration of HCl is 0.01707 M.
