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3 years ago

13

The owner of an apartment building can rent all 50 apartments if she charges $600 per month, but she rents one fewer apartment f

or each $20 increase in monthly rent. Identify the maximum revenue for this function?

1 answer:

Gwar [14]3 years ago

8 0

Answer:

30,000

Step-by-step explanation:

If she gets all 50 at 600 per month, 50x600 is 30,000.

I hope this helped!

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kolbaska11 [484]

$\bf \cfrac{3\pm1}{\frac{1}{3}}\implies 
\begin{cases}
\cfrac{3+1}{\frac{1}{3}}\\\\
\cfrac{3-1}{\frac{1}{3}}
\end{cases}\\\\
-------------------------------\\\\$

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\\\\\\
\cfrac{3-1}{\frac{1}{3}}\implies \cfrac{2}{\frac{1}{3}}\implies \cfrac{\frac{2}{1}}{\frac{1}{3}}\implies \cfrac{2}{1}\cdot \cfrac{3}{1}\implies \cfrac{2\cdot 3}{1\cdot 1}\implies \cfrac{6}{1}\implies \boxed{6}$

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A survey was done to determine the effect of students changing answers while taking a multiple-choice test on which there is on

Umnica [9.8K]

Answer:

6% of the changes were from incorrect to incorrect

Step-by-step explanation:

The sum of the percentages must be 100%.

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Evaluate b - 2 a - c for a = -3, b = 9, and c = -6

saw5 [17]

9-2(-3)+6= 9+6+6 Your answer should be 21 if I read your question correctly

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MissTica

Your answer would be A 1040.

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torisob [31]

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3 years ago