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Sidana [21]
2 years ago
15

What is the output value of 2x^2-9x-5 input value is x=2

Mathematics
1 answer:
Kobotan [32]2 years ago
5 0

Answer:

-15

Step-by-step explanation:

Go to (Mâthway) This page can help you with problems like that. (replace the â with a when searching the site.)

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An ice cream shop uses 6 bananas to make 4 identical sundaes. How many bananas are used used each sundaes?
Marina86 [1]

Answer:

1.5 bananas to make each sundaes

Step-by-step explanation:

6 divided by 4

7 0
2 years ago
How many elements are in the union of five sets if the sets contain 10,000 elements each, each pair of sets has 1000 common elem
masya89 [10]

Answer:

40951

Step-by-step explanation:

Using the principles of inclusion - Exclusion

Where C(n,r)=n!/(n-r)!r!

Total elements in the five sets including number repetition is given as (10000)×C(5, 1) =10000× 5!/(5-1)!1!=10000×5=50000

Total Number of elements in each pair including number repetition of sets is given as

=(1000) × C(5, 2) =10000

Number of elements in each triple of sets is given as

=(100) × C(5, 3) =1000

Number of elements in every four sets

=(10) × C(5, 4)=50

Number of elements in every one set

(1) × C(5, 5)=1

Therefore total number of unique elements=50000-10000+1000-50+1

=40951

5 0
3 years ago
Divide mentally. 6.2 ÷ 2,000 = ? A. 0.31 B. 0.031 C. 0.0031 D. 0.00031
soldi70 [24.7K]
C. 0.0031 

6.2 divided by 2,000 = 0.0031
5 0
3 years ago
Please show work if you do, ( and get it right) I will make you brainliest!!!
DerKrebs [107]

Answer:

The percentage increase in bird population in the second years is 4%  .

Step-by-step explanation:

Given as :

During two years, the population of birds of an island became 7 times more than before.

The the percentage increase in first year = = r_1 =40%

Let The percentage increase in second year =  r_2 = r%

So, According to question

The initial population of bird = x

The increase population of bird =7 times before = 7 x

Now,

The increase population of bird = initial population of bird × (1+ \dfrac{r_1}{100}) ×  (1+ \dfrac{r_2}{100})

Or, 7 x = x × (1+ \dfrac{40}{100}) ×  (1+ \dfrac{r}{100})

Or, \dfrac{7 x}{x} = 1.4 ×  (1+ \dfrac{r}{100})

Or, 7 = 1.4 ×  (1+ \dfrac{r}{100})

Or, \dfrac{7 }{1.4} = (1+ \dfrac{r}{100})

Or, 5 = (1+ \dfrac{r}{100})

Or, (1+ \dfrac{r}{100}) = 5

Or, \dfrac{r}{100} = 5 - 1

Or,  \dfrac{r}{100} = 4

∴ r = 4 × 100

I.e r = 400

so, The percentage increase = r% = 4

Hence The percentage increase in bird population in the second years is 4%  . Answer

3 0
3 years ago
The question is on the image
allochka39001 [22]
2th bounce- 80
5th Bounce- (-)200
9th Bounce- (-)560

Every time the ball bounces it loses 40cm because on the first bounce 160cm-120cm=40cm
And the score goes down by 40 every time and since we go into the negatives the negatives sometimes add on top of each other
5 0
2 years ago
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