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2 years ago

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During a winter storm, the amount of snowfall was recorded in 555 different locations. All measurements have been rounded to the

nearest \dfrac12 2 1 start fraction, 1, divided by, 2, end fraction inch. How many times as great is the amount of snow at the location that received the most snow as the location that received the least snow?

1 answer:

Yuri [45]2 years ago

4 0

Answer:

Step-by-step explanation:

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Which ofnthe following shows the correct use of distributive property when solving 1/3(33-x)=135,2

madam [21]

Answer: OPTION C.

Step-by-step explanation:

The missing options are:

$A. (33 - x) = \frac{1}{3} * 135.2\\\\B. (\frac{1}{3} *33) - \frac{1}{3} x = \frac{1}{3} * 135.2\\\\C.(\frac{1}{3} * 33) - \frac{1}{3} x = 135.2\\\\D. (\frac{1}{3} * 33) + \frac{1}{3} x = 135.2$

In order to solve this exercise you need to remember the following:

1. The Distributive property states that:

$a(b+c)=ab+ac\\\\a(b-c)=ab-ac$

2. The multiplication of signs:

$(+)(+)=+\\(-)(-)=+\\(-)(+)=-\\(+)(-)=-$

In this case the exercise gives you the following equation:

$\frac{1}{3}(33-x)=135.2$

Since you need to solve for the variable "x" in order to find its value, the first step you must apply in the in the procedure is to eliminate the parentheses applying the Distributive property.

Then, you must multiply everyting inside the parentheses by $\frac{1}{3}$ .

Therefore,based on the explanation, you know that the correct use of the Distributive property is:

$\frac{1}{3}*33-\frac{1}{3}x=135.2$

8 0

2 years ago

the sum 2 number is 27. the largest number is 3 larger then the smaller one. what are the 2 numbers and what are the systems of

Alex17521 [72]

X + 3x = 27
4x = 27
÷ 4
x = 6.75 (smaller number)
27 - 6.75 = 20.25 (larger number).
I don't know the 'systems of equations' though, sorry.

4 0

2 years ago

A person invested $420 in an account growing at a rate allowing the money to double

AURORKA [14]

Answer:

t=11.9

Step-by-step explanation:

960=420(2)^t/10

2.28571429=2^t/10

add log to both sides

log(2.28571429)=10 t log(2)

divide by log 2

1.19264508= 10 /t

10(1.19264508)

11.926450779=t

8 0

1 year ago

Can someone please help me<br> A.33<br> B.86<br> C.53<br> D.89

polet [3.4K]

The answer is B , simply add the two angles up

3 0

2 years ago

Basic Computation: Find Probabilities In Problems 5-14, assume that x has a normal distribution with the specified mean and stan

Ulleksa [173]

Answer:

the answer is below

Step-by-step explanation:

The z score is used to calculate by how many standard deviations the raw score is above or below the mean. The z score is given as:

$z=\frac{x-\mu}{\sigma}\\\\\mu=mean,\sigma=standard\ deviation$

1) For x = 3

$z=\frac{x-\mu}{\sigma}=\frac{3-4}{2}=-0.5$

For x = 6

$z=\frac{x-\mu}{\sigma}=\frac{6-4}{2}=1$

P(3 ≤ x ≤ 6) = P(-0.5 ≤ z ≤ 1) = P(z < 1) - P(z < -0.5) = 0.8413 - 0.3085 = 0.5328

2) For x = 50

$z=\frac{x-\mu}{\sigma}=\frac{50-40}{15}=0.67$

For x = 70

$z=\frac{x-\mu}{\sigma}=\frac{70-40}{15}=2$

P(50 ≤ x ≤ 70) = P(0.67 ≤ z ≤ 2) = P(z < 2) - P(z < 0.67) = 0.9772 - 0.7486 = 0.2286

3) For x = 8

$z=\frac{x-\mu}{\sigma}=\frac{8-15}{3.2}=-2.19$

For x = 12

$z=\frac{x-\mu}{\sigma}=\frac{12-15}{3.2}=-0.94$

P(8 ≤ x ≤ 12) = P(-2.19 ≤ z ≤ -0.94) = P(z < -0.94) - P(z < -2.19) = 0.1736 - 0.0143 = 0.1593

4) For x = 30

$z=\frac{x-\mu}{\sigma}=\frac{30-20}{3.4}=2.94$

P(x ≥ 30) = P(z ≥ 2.94) = 1 - P(z < 2.94) = 1 - 0.9984 = 0.0016

5) x = 90

$z=\frac{x-\mu}{\sigma}=\frac{90-100}{15}=-0.67$

P(x ≥ 90) = P(z ≥ -0.67) = 1 - P(z < -0.67) = 1 - 0.2514 = 0.7486

6) For x = 10

$z=\frac{x-\mu}{\sigma}=\frac{10-15}{4}=-1.25$

For x = 20

$z=\frac{x-\mu}{\sigma}=\frac{20-15}{4}=1.25$

P(10 ≤ x ≤ 20) = P(-1.25 ≤ z ≤ 1.25) = P(z < 1.25) - P(z < -1.25) = 0.8944 - 0.1056 = 0.7888

7) For x = 7

$z=\frac{x-\mu}{\sigma}=\frac{7-5}{1.2}=1.67$

For x = 9

$z=\frac{x-\mu}{\sigma}=\frac{9-5}{1.2}=3.33$

P(7 ≤ x ≤ 9) = P(1.67 ≤ z ≤ 3.33) = P(z < 3.33) - P(z < 1.67) = 0.9996 - 0.9525 = 0.0471

8) For x = 40

$z=\frac{x-\mu}{\sigma}=\frac{40-50}{15}=-0.67$

For x = 47

$z=\frac{x-\mu}{\sigma}=\frac{47-50}{15}=-0.2$

P(40 ≤ x ≤ 47) = P(-0.67 ≤ z ≤ -0.2) = P(z < -0.2) - P(z < -0.67) = 0.4207 - 0.2514 = 0.1693

9) x = 120

$z=\frac{x-\mu}{\sigma}=\frac{120-10}{15}=7.33$

P(x ≥ 120) = P(z ≥ 7.33) = 1 - P(z < 7.33) = 1 - 0.9999 = 0.001

10) x = 2

$z=\frac{x-\mu}{\sigma}=\frac{2-3}{0.25}=-4$

P(x ≥ 2) = P(z ≥ -4) = 1 - P(z < -4) = 1 - 0.0001 = 0.999

3 0

2 years ago