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3 years ago

Classify the following triangles. Check all that apply.

Mathematics

1 answer:

JulijaS [17]3 years ago

7 0

It could be classified as right or scalene- it has no congruent sides (scalene) and a right triangle has only one right angle in it, and it does.

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A jar contains 6 red marbles numbered 1 to 6 and 4 blue marbles numbered 1 to 4. A marble is drawn at random from the jar. Find

svetoff [14.1K]

Answer:

Step-by-step explanation:

The marble is red. There are 6 red marbles out of ten. So the answer is

6/10 = 0.60

Red: 1 3 5

Blue: 1 3

So there are 5 ways that you can draw an odd number. The problem is that they are not evenly distributed.

Red: 1/2 * 3/6 = 1/4 = 0.25

Blue: 1/2 * 2/4 = 0.25

Red + blue = 1/4 + 1/4 = 1/2

You could have gotten 1/2 by taking 5/10 but that won't always work.

4 0

3 years ago

If <img src="https://tex.z-dn.net/?f=x-12%5Csqrt%7Bx%7D%20%2B36%3D0" id="TexFormula1" title="x-12\sqrt{x} +36=0" alt="x-12\sqrt{

Elis [28]

Answer:

x = 36

Step-by-step explanation:

$x - 12\sqrt{x} + 36 = 0$

Subtract x and 36 from both sides.

$-12\sqrt{x} = -x - 36$

Divide both sides by -1.

$12\sqrt{x} = x + 36$

Square both sides.

$144x = x^2 + 72x + 1296$

Subtract 144x from both sides.

$0 = x^2 - 72x + 1296$

Factor the right side.

$0 = (x - 36)^2$

$x - 36 = 0$

$x = 36$

Since the solution of the equation involved squaring both sides, we musty check the answer for possible extraneous solutions.

Check x = 36:

$x - 12\sqrt{x} + 36 = 0$

$36 - 12\sqrt{36} + 36 = 0$

$36 - 12\times 6 + 36 = 0$

$36 - 72 + 36 = 0$

$0 = 0$

Since 0 = 0 is a true statement, the solution x = 36 is a valid solution.

6 0

4 years ago

The stadium has 53,000 seats seats sell for $42 in section 8 $36 in section B $30 in section C the number of seats in this in se

Zielflug [23.3K]

Answer:

Section A = 26,500 seats

Section B = 14,900 seats

Section C = 11,600 seats

Step-by-step explanation:

Total seats = 53,000

Total revenue = 1,997,400

Section A seat = $42

Section B seat = $36

Section C seat = $30

The number of seats in this in section A equals the total number of seats in section BNC

A = B + C

A + B + C = 53,000 (1)

42A + 36B + 30C = 1,997,400 (2)

Substitute A = B + C into (1)

A + B + C = 53,000

B + C + B + C = 53,000

2B + 2C = 53,000

2(B + C ) = 53,000

B + C = 53,000 / 2

= 26,500

B + C = 26,500 (3)

Substitute B + C = 26,500 into (2)

42A + 36B + 30C = 1,997,400

Recall,

A = B + C

42( 26,500) + 36B + 30C = 1,997,400

1,113,000 + 36B + 30C = 1,997,400

36B + 30C = 1,997,400 - 1,113,000

36B + 30C = 884,400. (4)

Multiply (3) by 30

B + C = 26,500 × 30

30B + 30C = 795,000 (5)

36B + 30C = 884,400 (4)

Subtract (5) from (4) to eliminate C

36B - 30B = 884,400 - 795,000

6B = 89,400

B = 89,400/6

= 14,900

B = 14,900

From (3)

B + C = 26,500

C = 26,500 - B

= 26,500 - 14,900

= 11,600

A = B + C

= 14,900 + 11,600

= 26,500

Section A = 26,500 seats

Section B = 14,900 seats

Section C = 11,600 seats

8 0

3 years ago

Three ways to write 3 to the 5th power

cestrela7 [59]

First expression

=> 3 x 3 x 3 x 3 x 3 – In this expression, we multiplied 3 5 times and the product is 243

Second expression

=> 3 ^ 5 , in where ^ read as raised to the power. , the product is also 243

Third expression

=> 3^2 x 3 ^3

=> (3 x 3) x (3 x 3 x 3)

=> 9 x 27, the product is also equals to 243.

7 0

3 years ago

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WILL MARK BRAINLIEST!!! PLEASE ANSWER!!! WRONG ANSWERS JUST FOR POINTS WILL BE REPORTED!!!!!!!!!!!!!!

Alchen [17]

Answer:

where's the question???

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers