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Bogdan [553]
4 years ago
15

One number is 8 less than a second number. Twice the second number is 52 more than 5 times the first. Find the smaller of the tw

o numbers.
Mathematics
2 answers:
Lemur [1.5K]4 years ago
5 0

I will try my best...


Let x and y be the two numbers.  


x = y - 4  


2y = 5x - 10  


Now, we solve the system of equations:  


2y = 5(y - 4) - 10  


2y = 5y - 20 - 10  


-3y = -30  



So...


y = 10  


x = 10 - 4 = 6


JulijaS [17]4 years ago
3 0

Let x and y be the two numbers.  

x = y - 4  

2y = 5x - 10  

solve the system of equations:  

2y = 5(y - 4) - 10  

2y = 5y - 20 - 10  

-3y = -30  

y = 10  

x = 10 - 4 = 6

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A,b,c are all positive integers
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Answer:

  77

Step-by-step explanation:

We can use a number of ratio units to represent b that is the LCM of 8 and 6. That value is 24. Then multiplying the first ratio by 3 and the second by 4, we have ...

  a:b = 9:24   and   b:c = 24:44

Then the ratios of all are ...

  a : b : c = 9 : 24 : 44

and the sum is 9+24+44 = 77.

8 0
3 years ago
17
Sauron [17]

let's firstly find the equation of the parabola, bearing in mind that x-intercepts or solutions/zeros/roots means y = 0.

\bf ~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=1\\ k=-9 \end{cases}\implies y=a(x-1)^2-9 \\\\\\ \textit{we also know that } \begin{cases} x=0\\ y=-6 \end{cases}\implies -6=a(0-1)^2-9\implies 3=a(-1)^2

\bf 3=a\qquad \qquad \textit{therefore}\qquad \qquad \boxed{y=3(x-1)^2-9} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{y}{0}=3(x-1)^2-9\implies 9=3(x-1)^2\implies \cfrac{9}{3}=(x-1)^2\implies 3=(x-1)^2 \\\\\\ \pm\sqrt{3}=x-1\implies \pm\sqrt{3}+1=x\implies x= \begin{cases} \sqrt{3}+1\\ -\sqrt{3}+1 \end{cases}\implies x\approx \begin{cases} 2.73\\ -0.73 \end{cases}

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3 years ago
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Multiply 2/3 by 42,and then multiply that product by 10​
EastWind [94]
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4 years ago
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weqwewe [10]

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Step-by-step explanation:

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