Answer:
C and D
Step-by-step explanation:
Answer:
Hopefully you can see the image.
Basically what's going on is the shape is being reflected over this line (x = -1) rather than the origin line.
Hope this helps :)
Answer:
56√2 ≈ 79.20
Step-by-step explanation:
The hypotenuse of an isosceles right triangle is √2 times the side length, so the side length here is ...
s·√2 = 28
s = 28/√2
The perimeter is 4 times the side length, so is ...
P = 4s = 4·28/√2
= 4·28·(√2)/2 . . . . . multiply by (√2)/(√2) to rationalize the denominator
= 56√2 ≈ 79.195959
The perimeter of the square is 56√2, about 79.20 units.
Answer:
Given the system of equation:
......[1]
......[2]
we can rewrite equation [2] as;
......[3]
Substitute equation [3] into [1] to eliminate x, and solve for y;

Using distributive property: 

Combine like terms;
16 - 8y = -4
Add 4 to both sides we have;
20 - 8y = 0
Add 8y to both sides we have;
20 = 8y
Divide 8 to both sides we have;

Substitute the y-value in [3] we have;

x = 8 - 5 = 3
Therefore, the expression should be substituted into the first equation is,
and also the value of x = 3 and y = 2.5
-32 = 4c -12
add -34 by 12 which is -20
divide it by 4
c = -5