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svet-max [94.6K]
3 years ago
13

How do i calculate the net force of the following question.Plz answer correctly

Physics
1 answer:
oee [108]3 years ago
5 0
<h2>Explanation:</h2><h2><em><u>force</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>m</u></em><em><u>a</u></em><em><u>s</u></em><em><u>s</u></em><em><u>×</u></em><em><u>acceleration</u></em></h2>

<em><u>m</u></em><em><u>a</u></em><em><u>s</u></em><em><u>s</u></em><em><u>=</u></em><em><u>3</u></em><em><u>0</u></em><em><u> </u></em><em><u>f</u></em><em><u>o</u></em><em><u>r</u></em><em><u>c</u></em><em><u>e</u></em><em><u>=</u></em><em><u>5</u></em><em><u>0</u></em>

<em><u>(</u></em><em><u>a</u></em><em><u>)</u></em><em><u> </u></em><em><u>5</u></em><em><u>0</u></em><em><u>÷</u></em><em><u>3</u></em><em><u>0</u></em><em><u> </u></em>

<h2><em><u>b</u></em><em><u>e</u></em><em><u>c</u></em><em><u>a</u></em><em><u>u</u></em><em><u>s</u></em><em><u>e</u></em><em><u> </u></em><em><u>w</u></em><em><u>e</u></em><em><u> </u></em><em><u>d</u></em><em><u>o</u></em><em><u>n</u></em><em><u>'</u></em><em><u>t</u></em><em><u> </u></em><em><u>h</u></em><em><u>a</u></em><em><u>v</u></em><em><u>e</u></em><em><u> </u></em><em><u>a</u></em><em><u>c</u></em><em><u>c</u></em><em><u>e</u></em><em><u>l</u></em><em><u>e</u></em><em><u>r</u></em><em><u>a</u></em><em><u>t</u></em><em><u>i</u></em><em><u>o</u></em><em><u>n</u></em><em><u> </u></em><em><u>w</u></em><em><u>h</u></em><em><u>i</u></em><em><u>c</u></em><em><u>h</u></em><em><u> </u></em><em><u>i</u></em><em><u>s</u></em><em><u> </u></em><em><u>k</u></em><em><u>n</u></em><em><u>o</u></em><em><u>w</u></em><em><u>n</u></em><em><u> </u></em><em><u>a</u></em><em><u>s</u></em><em><u> </u></em><em><u>m</u></em><em><u>/</u></em><em><u>s</u></em><em><u>2</u></em><em><u> </u></em><em><u>t</u></em><em><u>h</u></em><em><u>a</u></em><em><u>t</u></em><em><u> </u></em><em><u>s</u></em><em><u>t</u></em><em><u>a</u></em><em><u>n</u></em><em><u>d</u></em><em><u>s</u></em><em><u> </u></em><em><u>f</u></em><em><u>o</u></em><em><u>r</u></em><em><u> </u></em><em><u>m</u></em><em><u>e</u></em><em><u>t</u></em><em><u>e</u></em><em><u>r</u></em><em><u> </u></em><em><u>p</u></em><em><u>e</u></em><em><u>r</u></em><em><u> </u></em><em><u>s</u></em><em><u>e</u></em><em><u>c</u></em><em><u>o</u></em><em><u>n</u></em><em><u>d</u></em><em><u>s</u></em><em><u> </u></em><em><u>square</u></em><em><u> </u></em><em><u>.</u></em><em><u> </u></em><em><u>H</u></em><em><u>o</u></em><em><u>p</u></em><em><u>e</u></em><em><u> </u></em><em><u>t</u></em><em><u>h</u></em><em><u>i</u></em><em><u>s</u></em><em><u> </u></em><em><u>h</u></em><em><u>e</u></em><em><u>l</u></em><em><u>p</u></em><em><u> </u></em><em><u>pls</u></em><em><u> </u></em><em><u>f</u></em><em><u>o</u></em><em><u>l</u></em><em><u>l</u></em><em><u>o</u></em><em><u>w</u></em><em><u> </u></em><em><u>t</u></em><em><u>h</u></em><em><u>a</u></em><em><u>n</u></em><em><u>k</u></em><em><u> </u></em><em><u>y</u></em><em><u>o</u></em><em><u>u</u></em></h2>
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206 pm

Explanation:

We are given that

Potential difference,\Delta V=24.5+A V

Distance,d=4.5+B cm

We have to determine the de Brogile wavelength of the electron.

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\Delta V=24.5+11=35.5 V

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Mass of electron=m=9.1\times 10^{-31} kg

Speed of electron,v=\sqrt{\frac{2q\Delta V}{m}}

Using the formula

v=\sqrt{\frac{2\times 1.6\times 10^{-19}\times 35.5}{9.1\times 10^{-31}}

v=3.53\times 10^6 m/s

de Brogile wavelength, \lambda=\frac{h}{mv}

Where h=6.626\times 10^{-34}

\lambda=\frac{6.626\times 10^{-34}}{9.1\times 10^{-31}\times 3.53\times 10^6}=2.06\times 10^{-10}=206\times 10^{-12} m

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3 years ago
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Answer:

255.09 m

Explanation:

Using

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Substitute into equation 1,

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H = 12100(0.4132)/19.6

H = 255.09 m.

Hence the maximum elevation achieved by the projectile = 255.09 m

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