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kotykmax [81]
3 years ago
9

If x+9.8=14.7, what is the value of 8(x-3.7?

Mathematics
1 answer:
yulyashka [42]3 years ago
3 0
First find X by subtracting 9.8 from 14.7
X should equal 4.9
than fill in the equation for x
8(4.9-3.7)
you then subtract in the parenthasis
getting the answer of 1.2
finally multiply 1.2x8
Your final answer is 9.6
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Consider a circle whose equation is x2 + y2 – 2x – 8 = 0. Which statements are true? Select three options. The radius of the cir
FromTheMoon [43]

The statements which are correct about the equation of circle x^{2} +y^{2}-2x-8=0 are 1) The radius of the circle is 3 units,2) The center of the circle lies on the x axis,5) The radius of this circle is the same the radius of the circle whose equation is x^{2} +y^{2} =9.

Given the equation of circle be x^{2} +y^{2}-2x-8=0.

We are required to find the appropriate statements related to the equation x^{2} +y^{2}-2x-8=0.

x^{2} +y^{2}-2x-8=0 can be written as under:

x^{2} +y^{2} -2x+1-9=0

x^{2} +1^{2}-2x+y^{2} -9=0

(x-1)^{2}+y^{2}-9=0

(x-1)^{2} +y^{2} =9

(x-1)^{2}+y^{2}  =3^{2}

Equation of a circle usually in the form x^{2} +y^{2} =a^{2} in which a is radius.

From the comparison of both the equations we get that radius is 3 units.

From the equation point will be (1,0). It is on the x axis.

Hence the statements which are correct about the equation of circle x^{2} +y^{2}-2x-8=0 are 1) The radius of the circle is 3 units,2) The center of the circle lies on the x axis,5) The radius of this circle is the same the radius of the circle whose equation is x^{2} +y^{2} =9.

Learn more about radius at brainly.com/question/24375372

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Using drawings of rectangular prism, define in your own words, perimeter, area, and volume. Use color pencils to highlight what
yKpoI14uk [10]
This is what a rectangular prism looks like
Now for the definitions:
The perimeter is.... all of the lengths of sides added together.
The area is.... the sides all added together cubed
The volume...... the whole inside. (Think like it’s a shoe box and then you fill the shoe box up with water) that’s the volume

6 0
4 years ago
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point b on the ground is 5 cm from point E at the entrance to Ollie's house. He is 1.8 m tall and is standing at Point D, below
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Point B on the ground is 5 cm from point E at the entrance to Ollie's house.

Ollie is at a distance of 2.45 m from the entrance to his house when he first activates the sensor.

The complete question is as follows:

Ollie has installed security lights on the side of his house that is activated by a  sensor. The sensor is located at point C directly above point D. The area covered by the sensor is shown by the shaded region enclosed by triangle ABC. The distance from A to B is 4.5 m, and the distance from B to C is 6m. Angle ACB is 15°.

The objective of this information is:

  • To find angle CAB and;
  • Find the distance Ollie is from the entrance to his house when he first activates the sensor.

The diagrammatic representation of the information given is shown in the image attached below.

Using  cosine rule to determine angle CAB, we have:

\mathbf{\dfrac{AB}{Sin \hat {ACB}} = \dfrac{BC}{Sin \hat {CAB}}= \dfrac{CA}{Sin \hat {ABC}}}

Here:

\mathbf{\dfrac{AB}{Sin \hat {ACB}} = \dfrac{BC}{Sin \hat {CAB}}}

\mathbf{\dfrac{4.5}{Sin \hat {15^0}} = \dfrac{6}{Sin \hat {CAB}}}

\mathbf{Sin \hat {CAB} = \dfrac{Sin 15 \times 6}{4.5}}

\mathbf{Sin \hat {CAB} = \dfrac{0.2588 \times 6}{4.5}}

\mathbf{Sin \hat {CAB} = 0.3451}

∠CAB = Sin⁻¹ (0.3451)

∠CAB = 20.19⁰

From the diagram attached;

  • assuming we have an imaginary position at the base of Ollie Standing point called point F when Ollie first activates the sensor;          

Then, we can say:

∠CBD = ∠GBF

∠GBF = (CAB + ACB)      

(because the exterior angles of a Δ is the sum of the two interior angles.

∠GBF = 15° + 20.19°

∠GBF = 35.19°

Using the trigonometric function for the tangent of an angle.

\mathbf{Tan \theta = \dfrac{GF}{BF}}

\mathbf{Tan \ 35.19  = \dfrac{1.8 \ m }{BF}}

\mathbf{BF  = \dfrac{1.8 \ m }{Tan \ 35.19}}

\mathbf{BF  = \dfrac{1.8 \ m }{0.7052}}

BF = 2.55 m

Finally, the distance of Ollie║FE║ from the entrance of his bouse is:

= 5 - 2.55 m

= 2.45 m

Therefore, we can conclude that Ollie is at a distance of 2.45 m from the entrance to his house when he first activates the sensor.

Learn more about exterior angles here:

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Ned has scored 84 points in the first six games of basketball season how many points per game as Ned scored
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84 points/6 games

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Final Answer: 14 points per game or 14 points/game
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Answer:

kira has 17 books. I think

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