Answer:
option A
Explanation:
In carrying out these experimental procedure, the same restriction enzyme that is used to cut out the gene of interest should also be the same used for the cutting of the plasmid to generate sticky ends. Then the desired gene is inserted into the cut plasmid then treatment with DNA ligase. Purified DNA ligase is utilized in gene cloning to join/ligate DNA molecules together forming a recombinant DNA. Thus, step 3 should be carried out after step 4.
The shoreline is one of the harshest and most changeable environments for living creatures. The changing tides shift the environment dramatically within a sub-daily cycle. Here, we can consider two typical shoreline organisms, and the changing environment they must endure. Within the rocky shore environment, an octopus would be within the shallow but open sea environment during high tide, and water temperature and salinity conditions would be fairly constant. During low tide, the octopus might become trapped in a rock pool. This environment is dramatically different. The water temperature and salinity might increase drastically with exposure to solar radiation. The octopus is also more vulnerable to predation by humans and other land animals. Within the sandy shore environment, sand clams would be actively positioned at the interface of the sand and water, and will be actively filtering sea water for detritus. During low tide, the sand would be exposed to the air, and the clams would burrow down into the sand so as to avoid dessication.
Answer:
Option-D
Explanation:
Plasmodesmata are the plasma membrane lined pores present in the cells of the plants. Inside these pores runs a closed tubelike structure which is an extension of the endoplasmic reticulum.
The plasmodesmata allows cell to cell communication which involves symplast mode of transport that is through its cytoplasm.
The small water soluble molecules like amino acid and sugars can easily pass through these plasmodesmata via diffusion. The large molecules can be transported through these plamodesmata through selective diffusion.
Thus, Option-D is the correct answer.
Last night Jasmine and Jay amount combined is $150+$130=$280
amount donated to charity is 1/4 of $280= $70
amount spent at an amusement park is` 40/100 x $210= $84
the remaining money = 280- (70+84)= $126
35% of their original amount is 35/100x$280=$98
so Jay's claim is not correct because the remaining money is $126 and not $98 as she Jay claims.
