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Komok [63]
3 years ago
8

Danny Henry made a waffle on his six-inch-diameter circular griddle using batter containing a half a cup of flour. Using the sam

e batter, and knowing that all waffles have the same thickness, how many cups of flour would Paul Bunyan need for his 24-foot-diameter circular griddle
Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
7 0

Answer:

He'll need 288 cups to make a waffle on his 24 foot diameter circular griddle.

Step-by-step explanation:

In order to find out how much batter Danny needs we first need to compute the area of the first pans, since it is a circular pan their area is given by A = 2*pi*r. So we have:

Area of the first pan = 2*pi*(6/2) = 18.84 square inches

Area of the second pan = 2*pi*(24/2) = 75.36 square foots

We now need to convert these values to be in the same unit, we'll convert from square foots to square inches:

Area of the second pan = 75.36 * (12)^2 = 10851.84 square inches

We can now use a proportion knowing that the batter and the thickness of the waffles are the same. If 0.5 cup of flour can make a waffle on 18.84 square inches then x cup of flour can make a waffle on 10851.85 square inches. Writing this in a mathematical form, we have:

0.5/x = 18.84/10851.84

18.84x = 0.5*10851.85

x = 10851.85*0.5/18.84 =288 cups

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Answer:

5 \frac{5}{6}

Step-by-step explanation:

3 \frac{1}{2}  \times 1  \frac{2}{3}  \\  = 5 \ \frac{5}{6}

6 0
3 years ago
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Donna de paul is raising money for the homeless. She discovers that each church group requires 2 hours of let her writing and 1
Salsk061 [2.6K]

Answer:

x  =  7

y  =  3

z (max)  =  4950/3  =  1650

Step-by-step explanation:

Let call  

x numbers of church goup and

y numbers of Union Local

Then  

First contraint

2*x + 2*y ≤ 20

Second one

1*x + 3*y ≤ 16

Objective Function

z = 150*x + 200*y

Then the system is

z = 150*x + 200*y To maximize

Subject to:

2*x + 2*y ≤ 20

1*x + 3*y ≤ 16

x ≥ 0 y ≥ 0

We will solve by using the Simplex method

z - 150 *x - 200*y = 0

2*x + 2*y + s₁ = 20  

1*x + 3*y + 0s₁ + s₂ = 16

First Table

z           x          y          s₁           s₂          Cte

1        -150    -200       0            0     =      0

0          2         2           1            0     =    20

0          1          3          0            1      =     16

First iteration:

Column pivot   ( y column ) row pivot (third row) pivot 3

Second table

z           x                y          s₁           s₂                Cte

1       -250/3           0          0         200/3    =    3200/3

0      - 4/3               0          -1           2/3       =    -20/3

0         1/3               1            0           1/3       =    -20/3

Second iteration:

Column pivot  ( x column ) row pivot  (second row)  pivot  -4/3

Third table

z           x                y          s₁           s₂                Cte

1            0               0      750/12    700/6    =   4950/3

0            1                0        3/4          -1/2     =    7

0            0                1         -1/4          1/2     =  9/3

5 0
3 years ago
The roof of the building shown below has a span of 48 feet. The rafters upon which the roof is laid are 30 feet long, including
anyanavicka [17]

Solution :

Given :

Span of the roof = 48 feet

Length of the rafter = 30 feet (including the 4 feet overhung)

So, for the 30 feet long rafter, 26 feet will be rafter length from the high point of the roof to the edge of the roof and 4 feet will be the roof overhung.

Therefore, the horizontal span per rafter is

$=\frac{48}{2}$

= 24 feet

a). So the rise of the roof is $= \sqrt{(26)^2-(24)^2}$  

                                         = 10 feet

b). Pinch of the roof is $=\frac{\text{rise}}{\text{run}}$

                                     $=\frac{10}{24}$

                                     $=\frac{5}{12}$

c). The percent of the roof used as overhung is

     $=\frac{4+4}{60}\times 100$

     $=\frac{80}{6}$

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3 years ago
PLEASE HELP ME WITH THIS QUESTION
alekssr [168]

Answer:

The second option, 1,008 cm²

Step-by-step explanation:

   This shape has 5 sides to solve for with reguards to surface area.

   Let us solve for them all.

[1 & 2 - the triangles]

12 * 9 = 108 cm²

-> I am not going to divide since we have 2 congruent triangles

[3 - the bottom side]

25 * 12 = 300 cm²

[4 - the side facing away]

25 * 9 = 225 cm²

[5 - the side facing up]

25 * 15 = 375 cm²

   Now we will add them together for the total.

108 + 300 + 225 + 375 = 1,008 cm²

             The surface area for the triangular prism shown is 1,008 cm².

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2 years ago
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