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2 years ago

A phone plan charges an initial fee of $40 plus $.40 per minute. Which function equation represents this problem?

Mathematics

1 answer:

MrRissso [65]2 years ago

7 0

It’s the first option! f(x)= .40x + 40

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2 years ago

Triangle LMN is located at L(2,3), M(1,2), and N(4,4). The triangle is then transformed using the rule (x+5, y+2) to form the im

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3 years ago

You roll a red die and a green die. What is the size of the sample space of all possible outcomes of rolling these two dice, giv

VladimirAG [237]

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3 years ago

Shreya and beth each improved their yards by planting rose bushes and ornamental grass. They brought their supplies from the sam

frutty [35]

Answer:

The cost of one rose bush is $ 9 and the cost on one bunch pf ornamental grass is $ 8.

Explanation:

Name the variables and build a system of two equations with two unknowns.

1. Variable r: cost of one rose bush

2. Variable g: cost of one bunch of ornamental grass.

3. First equation:

Shreya spent $68 on 4 rose bushes and 4 bunches of ornamental grass.

4r + 4g = 68

4. Second equation:

Beth spent $115 on 11 rose bushes and 2 bunches of ornaments grass.

11r + 2g = 115

5. System of equations:

4r + 4 g = 68 equation 1

11r + 2g = 115 equation 2

6. Solve the system

a) Divide the equation 1 by 2:

2r + 2g = 34 equation 1a

11r + 2g = 115 equation 2

b) Subtract equation 1a from equation 2:

11r - 2r = 115 - 34

9r = 81

r = 81 / 9

r = 9

c) Substitute the value of r into the equation 1a:

2(9) + 2g = 34

9 + g = 17

g = 17 - 9

g = 8

7. Conclusion:

The cost of one rose bush is $ 9 and the cost on one bunch pf ornamental grass is $ 8.

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3 years ago

Please help me solve question 5.) with the letters a) & b)

tatyana61 [14]

Answer:

Step-by-step explanation:

5.(a)

x²+6x-15=0

$x=\frac{-6\pm\sqrt{36+4*15}}{2*1}\\x=\frac{-6\pm\sqrt{36+60} }{2}\\x=\frac{-6\pm\sqrt{96} }{2}\\x=\frac{-6\pm4\sqrt{6} }{2}\\x=-3\pm2\sqrt{6}$

(b)

4x²-8x-1=0

$x=\frac{8\pm\sqrt{64+4*4}}{2*4}\\x=\frac{8\pm\sqrt{80}}{8}\\x=\frac{8\pm 4\sqrt{5} }{8}\\x=\frac{2\pm\sqrt{5}}{2}$

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2 years ago