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Kisachek [45]
3 years ago
10

The amounts of household waste generated in a region during two years were 23,400,000 tons and 48,100,000 tons. What was the tot

al household waste generated over these two years in the region, expressed in scientific notation?
Mathematics
1 answer:
trasher [3.6K]3 years ago
8 0

The first step to do is to calculate first the total household waste generate for the two years. That is:

total waste generated = 23,400,000 tons + 48,100,000 tons

total waste generated = 71,500,000 tons

 

Now, to write either a very big number or a very small number in a form of scientific notation simply means to write it in a decimal form such as: 12.5 * 10^10

 

Now to write 71,500,000 in scientific notation, the decimal form is 7.15, however we still need to find out the * 10^n factor. The value of n depends on the number of places the decimal point was moved. If the movement was from right to left, the value of n is positive and if the movement was from right to left, the value of n is negative. Since the decimal point was moved by 7 places, hence the complete scientific notation is:

 

7.15 * 10^7 tons

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Answer:

9 4/7 + 8 5/6 = 773/

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Step-by-step explanation:

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Which system of equations is graphed on this coordinate plane​
Allisa [31]

Answer:

y=(3x/2)+3 and y=(-1x/2)-1

Step-by-step explanation:

So what I did was use rise/run to find the slope of the equation. Let's focus on the line going from the bottom left to the top right corner. For this line, I would start on (-2,0) which is one of the points plotted on your number line and count how much it is away from (0,3). You should get 3 units. After this, count how much it is to the right which is 2 units. Now, use rise/run to find the slope. 3/2, therefore the slope of the line is 3x/2.  Now all we need is the y-int. For the Y int, all we have to do is see where the line touches the Y-axis which in this case is at (0,3). So your y-int would be 3. Now we can use this information to craft an equation in the form y=mx+b, m being the slope and b  being the y int. We should get y=(3x/2)+3. Now repeat this with the other line to find the equation, but be careful!!! It has a negative slope.

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3 years ago
Solve the equation lol 54x+6x-30=7(x+2)+3x
stiv31 [10]

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Step-by-step explanation:

54x+6x-30=7(x+2)+3x

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Calculate the distance between each line and the point. round your answer to one decimal place.
Dmitry [639]

                                     Solving Equation A

Given the equation A

y=4x-2

and point (-3, 3)

The distance from the point (x₀, y₀) to the line Ax+By+C=0 is given by

d=\frac{\left|Ax_0+By_0+C\right|}{\sqrt{A^2+B^2}}

To apply this formula, we first need to express the line in standard form

y=4x-2

4x-y-2=0

After substituting: A=4, B=-1, C=2, x₀=-3, y₀=3

d=\frac{\left|\left(4\right)\left(-3\right)+\left(-1\right)\left(3\right)+\left(-1\right)\right|}{\sqrt{4^2+\left(-1\right)^2}}

d=\frac{\left|-12-3-2\right|}{\sqrt{4^2+\left(-1\right)^2}}

d=\frac{17}{\sqrt{4^2+\left(-1\right)^2}}

d=\sqrt{17}

d=4.1 units

Therefore, the distance between the line y = 4x - 2 and the point (-3, 3) will be:

  • d=4.1 units

                                             Solving Equation B

Given the equation B

y = -x + 5

and point (-1, -2)

The distance from the point (x₀, y₀) to the line Ax+By+C=0 is given by

d=\frac{\left|Ax_0+By_0+C\right|}{\sqrt{A^2+B^2}}

To apply this formula, we first need to express the line in standard form

y = -x + 5

x+y-5=0

After substituting: A=4, B=1, C=-5, x₀=-1, y₀=-2

d=\frac{\left|\left(1\right)\left(-1\right)+\left(1\right)\left(-2\right)+\left(-5\right)\right|}{\sqrt{1^2+\left(1\right)^2}}

d=\frac{\left|-1-2-5\right|}{\sqrt{1+1}}

d=\frac{\left|-8\right|}{\sqrt{2}}

d=\frac{8}{\sqrt{2}}

d=4\sqrt{2}

d=5.7 units

Therefore, the distance between the line y = -x + 5 and the point (-1, -2) will be:

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8 0
3 years ago
Given that sin(90 -5thetha) = Cos(180 - 0),<br>Find the value of theta​
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Answer:

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Step-by-step explanation:

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sin(90 - 5 θ) = cos(180)

Hint: | Express the right hand side in terms of sine.

Rewrite the right hand side using cos(θ) = sin(θ + π/2):

sin(90 - 5 θ) = sin(π/2 + 180)

Hint: | Eliminate the sine from the left hand side.

Take the inverse sine of both sides:

90 - 5 θ = -180 + π/2 + 2 π n_1 for n_1 element Z

or 90 - 5 θ = 180 + π/2 + 2 π n_2 for n_2 element Z

Hint: | Look at the first equation: Isolate terms with θ to the left hand side.

Subtract 90 from both sides:

-5 θ = -270 + π/2 + 2 π n_1 for n_1 element Z

or 90 - 5 θ = 180 + π/2 + 2 π n_2 for n_2 element Z

Hint: | Solve for θ.

Divide both sides by -5:

θ = 54 - π/10 - (2 π n_1)/5 for n_1 element Z

or 90 - 5 θ = 180 + π/2 + 2 π n_2 for n_2 element Z

Hint: | Look at the second equation: Isolate terms with θ to the left hand side.

Subtract 90 from both sides:

θ = 54 - π/10 - (2 π n_1)/5 for n_1 element Z

or -5 θ = 90 + π/2 + 2 π n_2 for n_2 element Z

Hint: | Solve for θ.

Divide both sides by -5:

Answer: θ = 54 - π/10 - (2 π n_1)/5 for n_1 element Z

or θ = -18 - π/10 - (2 π n_2)/5 for n_2 element Z

4 0
3 years ago
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