Two and a half energy bars it should be the right one.
Answer:
The volume of the concentrated 80 gallons mixture is 20 gallons
The volume of water in the 80 gallons mixture is 60 gallons
Step-by-step explanation:
The given parameters are;
The content of Container A = The cleaner
The concentration of the cleaner = 20% solution
The content of Container B = Pure water
The concentration of the desired solution = 5%
The volume of the required solution = 80 gallons
Let x represent the volume of the concentrated solution and y represent the volume of water in the 80 gallons mixture
Therefore, we have;
20/100 × x + y×0 = 5/100×80
x + y = 80
y = 80 - x
20/100 × x + (80 - x)×0 = 5/100×80
0.2·x = 4
x = 4/0.2 = 20
x = 20 gallons
y = 80 - x = 80 - 20 = 60
y = 60 gallons
The volume of the concentrated solution (80 gallons mixture) = x = 20 gallons
The volume of water in the 80 gallons mixture = y = 60 gallons.
Answer:
The square root is 12.649.....
5x + y = 9....multiply by 7
10x - 7y = -18
----------------
35x + 7y = 63 (result of multiplying by 7)
10x - 7y = -18
----------------add
45x = 45
x = 45/45
x = 1
5x + y = 9
5(1) + y = 9
5 + y = 9
y = 9 - 5
y = 4
solution is : (1,4)
=========================
-4x + 9y = 9
x - 3y = -6 ....multiply by 4
----------------
-4x + 9y = 9
4x - 12y = -24 (result of multiplying by 4)
---------------add
- 3y = - 15
y = -15/-3
y = 5
x - 3y = -6
x - 3(5) = -6
x - 15 = -6
x = -6 + 15
x = 9
solution is : (9,5)
