Question

A rectangle has a height of 4x^34x 3 4, x, cubed and a width of x^3+3x^2+2xx 3 +3x 2 +2xx, cubed, plus, 3, x, squared, plus, 2, x. Express the area of the entire rectangle. Your answer should be a polynomial in standard form. A rectangle with a height of 4 X cubed and a width of X cubed plus 3 X squared plus 2 X. The rectangle has 3 sections, one for each term of the width.

Answer 1

Answer:

$4x^6+12x^5+8x^4$

Step-by-step explanation:

Height of the rectangle$=4x^3$

Width of the rectangle $=x^3+3x^2+2x$

Area of a rectangle = Height X Width

$=4x^3(x^3+3x^2+2x)\\=4x^3*x^3+4x^3*3x^2+4x^3*2x\\=4x^{3+3}+12x^{3+2}+8x^{3+1}\\=4x^6+12x^5+8x^4$

The area of the entire rectangle is: $4x^6+12x^5+8x^4$ in standard form.