(2x^)(3x3) = help pleaseee

Use the formula pH = log (1/H*) to find the pH of the substance given its concentration

Vaselesa [24]

We can use the subtraction property of logs to expand the right side of the equation:

log(1/H*) = log(1) - log(H*)

No matter what base we’re using, log(1) = 0, so this simplifies to -log(H*). We’re also given a pH value of 3.6, so we can substitute this value into the original equation along with -log(H*) to get

3.6 = -log(H*)

Multiplying by -1 on both sides:

-3.6 = log(H*)

And rewriting in exponential form:

H* = 10^(-3.6) = 0.0003 (rounded to the nearest ten thousandth)

6 0

2 years ago

Y-2=-4 Help please tyy

kolezko [41]

Answer:

y = -2

Step-by-step explanation:

y - 2 = -4

add 2 to both sides

y - 2 + 2 = -4 + 2

y = -2

7 0

3 years ago

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The playing time X of jazz CDs has the normal distribution with mean 52 and standard deviation 7; N(52, 7).

natita [175]

Answer:

68% of jazz CDs play between 45 and 59 minutes.

Step-by-step explanation:

The correct question is: The playing time X of jazz CDs has the normal distribution with mean 52 and standard deviation 7; N(52, 7).

According to the 68-95-99.7 rule, what percentage of jazz CDs play between 45 and 59 minutes?

Let X = playing time of jazz CDs

SO, X ~ Normal( $\mu=52, \sigma^{2} =7$ )

The z-score probability distribution for the normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

Now, according to the 68-95-99.7 rule, it is stated that;

68% of the data values lie within one standard deviation points from the mean.

95% of the data values lie within two standard deviation points from the mean.

99.7% of the data values lie within three standard deviation points from the mean.

Here, we have to find the percentage of jazz CDs play between 45 and 59 minutes;

For 45 minutes, z-score is = $\frac{45-52}{7}$ = -1

For 59 minutes, z-score is = $\frac{59-52}{7}$ = 1

This means that our data values lie within 1 standard deviation points, so it is stated that 68% of jazz CDs play between 45 and 59 minutes.

6 0

3 years ago

Ann, Jim, and Miguel sent a total of 115

FromTheMoon [43]

Ann: 21
Jim: 31
Miguel: 63

Let’s start by finding Ann’s number.

a + (a + 10) + 3a = 115

5a + 10 = 115

5a = 115 - 10

5a = 105

a = 105 / 5

a = 21

Now, just find the others’ numbers using Ann’s.

Jim sent ten more messages than Ann, and 21 + 10 = 31.

Miguel sent 3 times as many messages as Ann, and 21 * 3 = 63.

3 0

3 years ago

What is the area of the composite figure? 7 yds; 12 yds. 18 yds.

Tju [1.3M]

For the square its 18x12 which is 216
For tge triangle its 18x7 which is 126 divided by 2 because its a triangle so 63
216+63=279yds^2

4 0

3 years ago

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