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3 years ago

What is the value of the expression 2^2+6^2÷2^2

Mathematics

1 answer:

Studentka2010 [4]3 years ago

3 0

Answer:

Step-by-step explanation:

$2^{2} + 6^{2} / 2^{2} = 4+ 36/4 = 4 +9 = 13$

4 + (6/2)^2 = 4+ 3^2 = 4+9 = 13

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$x^{2} +y^{2} =36$

Step-by-step explanation:

A circle centered at (0,0) with radius r is $x^{2} +y^{2} =r^{2}$

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If you want to move the location of the center, but keep it on the x-axis, then add or subtract a number to the x, such as this:

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1 year ago

. If α and β are the roots of

Lostsunrise [7]

Answer:

$18x^2+85x+18 = 0$

Step-by-step explanation:

Given Equation is

=> $2x^2+7x-9=0$

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=> a = 2, b = 7 and c = -9

So,

Sum of roots = α+β = $-\frac{b}{a}$

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Product of roots = αβ = c/a

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Now, Finding the equation whose roots are:

α/β ,β/α

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Sum of Roots = $\frac{\alpha^2+\beta^2 }{\alpha \beta }$

Sum of Roots = $\frac{(\alpha+\beta )^2-2\alpha\beta }{\alpha\beta }$

Sum of roots = $(\frac{-7}{2} )^2-2(\frac{-9}{2} ) / \frac{-9}{2}$

Sum of roots = $\frac{49}{4} + 9 /\frac{-9}{2}$

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The Quadratic Equation is:

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=> $18x^2+85x+18 = 0$

This is the required quadratic equation.

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What is the value of the expression 2^2+6^2÷2^2​

What is the value of the expression 2^2+6^2÷2^2