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iris [78.8K]
3 years ago
13

What is the force on a 1000 kg elevator that is falling freely at 9.8 m/sec2

Mathematics
1 answer:
deff fn [24]3 years ago
7 0

Answer: The only force on it is its weight, w=9800N

Step-by-step explanation:

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Using both the rotation matrices earlier in this lesson and your matrix calculator, find each determinant.
Trava [24]

Answer:

both are one

8 0
3 years ago
Read 2 more answers
(60 points)
natka813 [3]

Answer:

<h2>2. D. 64</h2><h2>5. B. 1, -3/2</h2><h2>6. C. 0, 2</h2>

Step-by-step explanation:

2.\\(a-b)^2=a^2-2ab+b^2\\\\x^2-16x=-8\\\\x^2-2(x)(8)=-8\\\\\text{We have}\ 2ab=2(x)(8).\ \text{Therefore}\ b=8.\\\\x^2-2(x)(8)=-8\qquad\text{add}\ 8^2=64\ \text{to both sides}\\\\x^2-2(x)(8)+8^2=-8+64\\\\(x-8)^2=56

5.\\2x^2+x-1=2\qquad\text{subtract 2 from both sides}\\\\2x^2+x-3=0\\\\2x^2+3x-2x-3=0\\\\x(2x+3)-1(2x+3)=0\\\\(2x+3)(x-1)=0\iff 2x+3=0\ \vee\ x-1=0\\\\2x+3=0\qquad\text{subtract 3 from both sides}\\2x=-3\qquad\text{divide both sides by 2}\\\boxed{x=-\dfrac{3}{2}}\\\\x-1=0\qquad\text{add 1 to both sides}\\\boxed{x=1}

6.\\2x^2-4x=0\qquad\text{divide both sides by 2}\\\\x^2-2x=0\\\\x(x-2)=0\iff x=0\ \vee\ x-2=0\\\\\boxed{x=0}\\\\x-2=0\qquad\text{add 2 to both sides}\\\boxed{x=2}

8 0
3 years ago
Help me wit dis plz for for 20 points​
Alisiya [41]

Answer:

I dont know but combine like terms and then solve it will make It alot easier

5 0
3 years ago
I am confused on how to do this? please help!
IceJOKER [234]
You would take random numbers preferable smaller ones such as -1,0,1,2
You would put those in the place of x
Then you would square the value of x. After that you subtract 4. Whatever you come out with is your y value. Then you put the x value on the x axis and from that point count up or down to the number you need on the y axis. Together that would be your point
6 0
3 years ago
**Answer quick I will mark brainliest ***
Juliette [100K]
184/525








(this is me adding characters)
5 0
3 years ago
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