Answer:
+
Step-by-step explanation:
What line? Please attach a picture or something, so we can figure out the equation for you.
Answer:
-3 1/3
Step-by-step explanation:
The quadratic
... y = ax² +bx +c
has its extreme value at
... x = -b/(2a)
Since a = 3 is positive, we know the parabola opens upward and the extreme value is a minimum. (We also know that from the problem statement asking us to find the minimum value.) The value of x at the minimum is -(-4)/(2·3) = 2/3.
To find the minimum value, we need to evaluate the function for x=2/3.
The most straightforward way to do this is to substitue 2/3 for x.
... y = 3(2/3)² -4(2/3) -2 = 3(4/9) -8/3 -2
... y = (4 -8 -6)/3 = -10/3
... y = -3 1/3
_____
<em>Confirmation</em>
You can also use a graphing calculator to show you the minimum.
Answer:
x=10
Step-by-step explanation:
1.5x-6=9
+6 +6
1.5x=15
/1.5 /1.5
x=10
When f(x) is substituted with a number, you just plug the number into wherever you see x:
_____________
f(12) = 3/2x + 14
f(12) = 3/2(12) + 14
f(12) = 18 + 14
f(12) = 32
f(-4) = 3/2x + 14
f(-4) = 3/2(-4) + 14
f(-4) = -6 + 14
f(-4) = 8
f(0) = 3/2(0) + 14
f(0) = 0 + 14
f(0) = 14