For squrae
area=side²
perimiter=4(side)
for circle
area=pir²
circumference=2pir
side=diameter, diameter/2=radius=side/2
find area not covered
that is areasquare-areacircle
areasquare=26²=676 sqauare inches
areaciecle, diameter=side, 26/2=13, area=pi13²=169*3.14=530.66 square inches
areanotcovered=676-530.66=145.34 square inches not coverd
ratio of perimiter to circumferece
perimiter=4*26=104
circumference=2pir=2pi13=26pi=26*3.14=81.64
circumference to perimiter is 81.64/104=0.785
Answer:
x=36
y=72
Step-by-step explanation:
I didnt do this type of problem in a while but Im pretty sure its correct
Answer:
transformation, cause you aren't altering it
Step-by-step explanation:
Answer:
d) ÷
Step-by-step explanation:
120 ÷ 3/11 = 440
Answer:
Option C
Step-by-step explanation:
complete question
A. 35[3]6cB. 12[3]12cC. 12[3]6cD.72c
The given equation can be written as
5^3√6c+7^3√6c
5 *
+ 7 * ![\sqrt{3 *3*2c}](https://tex.z-dn.net/?f=%5Csqrt%7B3%20%2A3%2A2c%7D)
5 * 3 *
+ 7 * 3 *![\sqrt{2c}](https://tex.z-dn.net/?f=%5Csqrt%7B2c%7D)
15 *
+ 21 *![\sqrt{2c}](https://tex.z-dn.net/?f=%5Csqrt%7B2c%7D)
36 *![\sqrt{2c}](https://tex.z-dn.net/?f=%5Csqrt%7B2c%7D)
12 [3]*![\sqrt{2c}](https://tex.z-dn.net/?f=%5Csqrt%7B2c%7D)
Option C is correct