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jok3333 [9.3K]
3 years ago
7

I need help finding functions​

Mathematics
1 answer:
velikii [3]3 years ago
3 0

Answer:

  1. y= 7
  2. y= -3
  3. y= -4
  4. y= -8

Step-by-step explanation:

y= -5x+1

=-5.-1+1

=7

Now you can do this method

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What is the area please help‼️‼️‼️
MariettaO [177]
The area of this is the length times the width times height?
Idk man
6 0
3 years ago
Use the given conditions to write an equations for the line in slope- intercept form. passing through (1,-8) and (-7,8)
Hoochie [10]

Answer:

y = -2x - 6

Step-by-step explanation:

Going from the first point to the second, we see x decreasing by 8 from 1 to -7 (this is the 'run') and y increasing by 16 from -8 to +8 (this is the 'rise').  Thus, the slope of the line through these two points is m = rise/run =  16/(-8) = -2.

Using the point-slope formula y - k = m(x - h) and the point (1, -8), we get:

y + 8 = -2(x - 1), or

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6 0
3 years ago
Please help meee! im confused!
kherson [118]

f(x)=y=√x looks something like this:

(4,2)

(9,3)

(16,4)

Whilst your graph is much higher slope, for lack of better term

Rules of transformation

f(x)+b - function is shifted b units upward (up y-axis)

f(x)-b - function is shifted b units downward (down y-axis)

f(x+b) - function is shifted b units to the left (negative x-axis)

f(x-b) - function is shifted b units to the right (positive x-axis)

-f(x) - function is reflected over x-axis

f(-x) - function is reflected over y-axis

bf(x) - vertical stretch for |b| > 1, vertical shrink for 0< |b| <1

f(bx) - horizontal shrink for |b| > 1, horizontal stretch for 0< |b| <1
**INVALIDATE my answer, as statements were given 10 mins after posted**

8 0
2 years ago
Read 2 more answers
Janet can make 1/3 of a necklace in 15 minutes. At this rate, how many can she make in an hour? *
miskamm [114]

Answer:

Janet can make 1  1/3 in an hour.

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
Helps with this math problem please
olasank [31]
First we are going to express both equation in terms of  y to compare their slopes:
For our first equation:
-x=1-y
-x-1=-y
y=x+1
For our second equation:
-1+y=x+2
y=x+3
So now we have our system of equations in terms of y:
\left \{ {{y=x+1} \atop {y=x+3}} \right.
Notice that the slope, the coefficient of x, in both equations is the same: 1, and if tow linear equations have the same slope, they are parallel.

We can conclude that we can classify the system of equations as parallel.
3 0
3 years ago
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