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zimovet [89]
3 years ago
8

Please help me!!! :(

Mathematics
1 answer:
eduard3 years ago
5 0

Answer:

1. ecologist

2.species

3. population

4.habitat

Step-by-step explanation:

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Atul has 2/3 lb of candy. Jose has 3/5 lb and Maria has 1/2 lb less then José. How many more pounds of candy does Atul have than
liraira [26]

Given:

Atul has \dfrac{2}{3} lb of candy.

Jose has \dfrac{3}{5} lb of candy.

Maria has \dfrac{1}{2} lb less than Jose.

To find:

How many more pounds of candy does Atul have than Maria?

Solution:

Since, Maria has \dfrac{1}{2} lb less than Jose, therefore

Maria has = \dfrac{3}{5}-\dfrac{1}{2} lb

Maria has = \dfrac{6-5}{10} lb

Maria has = \dfrac{1}{10} lb

Difference between the candies Atul and Maria have.

Difference = \dfrac{2}{3}-\dfrac{1}{10} lb

Difference = \dfrac{20-3}{30} lb

Difference = \dfrac{17}{30} lb

Therefore,  Atul have \dfrac{17}{30} lb of candy more than Maria.

6 0
3 years ago
HELPPPPP FAST PLEASEEEEEEEEEEEE
Drupady [299]

Answer:

45?

Step-by-step explanation:

7 0
2 years ago
Please help ASAP with this question
jeka57 [31]

Answer:

B. 7.9 in^2

Step-by-step explanation:

Part I.

Finding the fraction of the circle that is the sector

To start, let’s find the fraction of the circle that the sector covers. Since the measure of the central angle is 36, we get 36/360 or 1/10 of the circle.

Part II.

Finding the area of the Circle

The area of a circle is pi*r^2. Since r=5, then the area is 25pi.

Part III.

Finding the area of the sector.

Since the sector is 1/10 of the circle, its area is 1/10 of the circle’s area. So the area of the sector is 25/10*pi or (5/2)pi. This is approximately 7.9 in^2.

6 0
3 years ago
The Three sides of a triangle are, n, 4n-2, 4n-7. if the perimeter of the traingle is 45cm, what is the length of each side?​
kogti [31]

Answer:

52

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Please help. I don’t understand and don’t know what do to.
Bingel [31]

9514 1404 393

Answer:

  72

Step-by-step explanation:

The triangles are said to be similar. (ΔNPQ ~ ΔRSQ) That means corresponding sides have the same ratio:

  NP/RS = NQ/RQ = PQ/SQ = 24/32 = 21/28 = 3/4

This ratio, or scale factor, also applies to the perimeters of the two triangles.

  perimeter NPQ / perimeter RSQ = 3/4

Using the given expressions for the perimeters, we have ...

  (7x +2)/(10x -4) = 3/4

We can solve this equation in the usual way to find the value of x. Then we can use that value to find the perimeter of ΔNPQ.

  4(7x +2) = 3(10x -4) . . . . . multiply both sides by 4(10x -4)

  28x +8 = 30x -12 . . . . . eliminate parentheses

  20 = 2x . . . . . . . . . . . add 12-28x to both sides

  10 = x . . . . . . . . . . . divide both sides by 10

The perimeter of ΔNPQ is ...

  7x +2 = 7(10) +2 = 72

The perimeter of triangle NPQ is 72 units.

7 0
3 years ago
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