There would be one solution, and the one the gave would be correct.
Hope I helped!
Let me know if you need anything else!
~ Zoe
Answer:
Part 1) 
Part 2) 
Step-by-step explanation:
I will analyze two problems
see the attached figure to better understand the problem
Problem 1
The hypotenuse is the segment AB and the right angle is C
we know that
In the right triangle ABC
---> by SOH (opposite side divided by the hypotenuse)
substitute the given values

Remember that

substitute


Problem 2
The hypotenuse is the segment BC and the right angle is A
we know that
In the right triangle ABC
---> by TOA (opposite side divided by the adjacent side)
substitute the given values

Remember that

substitute


Given:
The vertices of a polygon are A (−1, 1), B (4, 1), C (4,−2), and D(−1,−2).
To find:
The perimeter of ABCD.
Solution:
Distance formula:

Using distance formula, we get




Similarly,



Now, perimeter of ABCD is



Therefore, the perimeter of ABCD is 16 units.
Answer:
A digit 2
Step-by-step explanation:
628/8 = 78
thus making 628 divisible by 8