All categories

3 years ago

State whether the following are describing distance (d), velocity (v), or acceleration (a)

Mathematics

1 answer:

jarptica [38.1K]3 years ago

3 0

Answer:

1. Velocity

2. Distance

3. Acceleration

Step-by-step explanation:

You might be interested in

Barbara plotted an elevation below sea level on a number line and labeled it A. She plotted point B above o, a distance that is

stellarik [79]

Answer: Because Point A is negative and the same distance below 0 on the number line as Point B is above it, Point B is both positive and the opposite of Point A.

7 0

3 years ago

Read 2 more answers

Last year, Michael opened an investment account with $5400. At the end of the year, the amount in the account had decreased by 2

trapecia [35]

He would have $4131 left from $5400 with a decrease with 23.5%

8 0

3 years ago

Identify the solutions to the quadratic equation 6x^2+x-1=0

tigry1 [53]

Answer:

1/3 and -1/2

Step-by-step explanation:

You can use the factoring method to identify the solutions of x

6x^2+x-1

2 numbers have to multiply to 6 and subtract to 1 because x is the same as 1x

So, you get 3x and 2x

since you know that -1x1 is -1 you will get

(3x-1)(2x+1)=0

Now, since (3x-1) and (2x+1) multiply to get 0, if either (3x-1) or (2x+1) is 0 the statement will be valid

3(1/3)-1=0

2(-1/2)+1=0

So, your answers are 1/3 and -1/2

5 0

2 years ago

A line passes through the point (–6, –3) and has a slope of 2/3 . Which point is on the same line?

navik [9.2K]

Answer:

The point (0, 1) represents the y-intercept.

Hence, the y-intercept (0, 1) is on the same line.

Step-by-step explanation:

We know that the slope-intercept form of the line equation

y = mx+b

where

m is the slope

b is the y-intercept

Given

The point (-6, -3)

The slope m = 2/3

Using the point-slope form

$y-y_1=m\left(x-x_1\right)$

where

m is the slope of the line

(x₁, y₁) is the point

In our case:

m = 2/3

(x₁, y₁) = (-6, -3)

substituting the values m = 2/3 and the point (-6, -3) in the point-slope form

$y-y_1=m\left(x-x_1\right)$

$y-\left(-3\right)=\frac{2}{3}\left(x-\left(-6\right)\right)$

$y+3=\frac{2}{3}\left(x+6\right)$

Subtract 3 from both sides

$y+3-3=\frac{2}{3}\left(x+6\right)-3$

$y=\frac{2}{3}x+4-3$

$y=\frac{2}{3}x+1$

comparing with the slope-intercept form y=mx+b

Here the slope = m = 2/3

Y-intercept b = 1

We know that the value of y-intercept can be determined by setting x = 0, and determining the corresponding value of y.

Given the line

$y=\frac{2}{3}x+1$

at x = 0, y = 1

Thus, the point (0, 1) represents the y-intercept.

Hence, the y-intercept (0, 1) is on the same line.

5 0

3 years ago

A cylinder car for two with a diameter of 8 cm and a height of 20 cm is used to package a gift what is the approximate volume of

LUCKY_DIMON [66]

V=PI x r^2 x H

V=3.14 x 64 x 20 = 1005 cubic cm

4 0

3 years ago