Answer: the last one
Step-by-step explanation:
Because it has a similar number in the x variable. If it didn’t have the same number in the x variable it would be a function.
Answer/Step-by-step explanation:
To represent the data given on a stem and leaf plot, the whole number in a given value would be used as the stem, while the number after the decimal point is the leaf. (Key: 3|3 = 3.3).
For example, in the first stem in the first row, we have 4 as the stem. All values that starts with 4 point would be represented in this row. The digit after 4 point for each of the values would be written on the leaf column in the first row, from the least to the largest. For the first row we have: 4 | 3 9.
Same applies to the rest rows.
The stem plot would look like the one below:
Ice Thickness:
Stem | Leaf
4 | 3 9
5 | 1 8 8 8 9
6 | 5 8 9 9
7 | 0 2 2 2 2 5 9
8 | 0 7
The data of the stem-and-leaf plot shows a bell-shaped pattern with majority of the ice thickness for the 20 locations clustering around the center of the data distribution.
Answer:
8 - (3 x 2) - (1 + 1) = 0
or
8 - 3 x 2 - (1 + 1) = 0
Remember PEMDAS.
If I put parenthesis around 3 x 2, I get 6.
But 8 - 6 = 2
How can we make 2 - 1 + 1 = 0?
If we look at PEMDAS, we know (2 - 1) + 1 = 2, but the answer needs to be 0.
So now try 2 - (1 + 1) and that gives me 0.
And it says parentheses...but you can also do 8 - 3 x 2 - (1 + 1) = 0.
Answer:
Range of the average number of tours is between 150 and 200 including 150 and 200.
Step-by-step explanation:
Given:
The profit function is modeled as:
The profit is at least $50,000.
So, as per question:
Now, rewriting the above inequality in terms of its factors, we get:
Now,
![x0\\x>200,(x-150)(x-200)>0\\For\ 150\leq x\leq200,(x-150)(x-200)\leq 0\\\therefore x=[150,200]](https://tex.z-dn.net/?f=x%3C150%2C%28x-150%29%28x-200%29%3E0%5C%5Cx%3E200%2C%28x-150%29%28x-200%29%3E0%5C%5CFor%5C%20150%5Cleq%20x%5Cleq200%2C%28x-150%29%28x-200%29%5Cleq%200%5C%5C%5Ctherefore%20x%3D%5B150%2C200%5D)
Therefore, the range of the average number of tours he must arrange per day to earn a monthly profit of at least $50,000 is between 150 and 200 including 150 and 200.
Answer: 59 cars per month
Step-by-step explanation:
