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3 years ago

Find the measure of<1

Mathematics

1 answer:

damaskus [11]3 years ago

3 0

The answer is 4
30x+20=20x+60
when you simplify you get 20x=30x-40
simplify again and you get -10x=-40
divide each side by -10 and you get
x=4

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Please use statement and reason, not sin cos or tan. In rectangle ABCD the diagonals intersect each other at point O and ABD = 3

zvonat [6]

Answer:

8 in

Step-by-step explanation:

Rectangle has properties:
Diagonals are congruent
Opposite sides are congruent
All angles are right

<h3>Given</h3>

m∠ABD = 30°
AC = 16 in
BC = ?

<h3>Solution</h3>

<u>As per properties mentioned above we have:</u>

BC = AD
BD = AC = 16 in

ΔABD is right triangle with ∠B - 30°, ∠A- 90°, ∠D - 60°

Side opposite to 30 is half of the length of the hypotenuse

<u>AD is opposite to ∠B and BD is the hypotenuse, then:</u>

AD = 1/2*BD
AD = 1/2(16)
AD = 8 in

and

BC = AD = 8 in

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3 years ago

What is 60÷746 with no decimals

Svetllana [295]

Answer: the answer to this solution is 8.04

5 0

3 years ago

Read 2 more answers

What is the next fraction in this sequence?<br> 1<br> 3<br> 9<br> 27<br> 280, 280, 280,<br> 280 /

WITCHER [35]

Answer:

the answer is 81 over 280

8 0

2 years ago

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konstantin123 [22]

Answer:

3.6 - 0.65 = 2.95

Step-by-step explanation:

subtract

3.6 - 2.95 = 0.65

6 0

3 years ago

When Alice spends the day with the babysitter, there is a 0.6 probability that she turns on the TV and watches a show. Her littl

slava [35]

Answer:

a) There is a 48% probability that both Alice and Betty watch TV tomorrow.

b) There is a 48% probability that Betty watches TV tomorrow.

c) There is a 12% probability that only Alice watches TV tomorrow.

Step-by-step explanation:

We have these following probabilities:

A 60% probability that Alice watches TV.

If Alice watches TV, an 80% probability Betty watches TV.

If Alice does not watch TV, a 0% probability that Betty watches TV, since she cannot turn the TV on by herself.

a) What is the probability that both Alice and Betty watch TV tomorrow?

Alice watches 60% of the time. Betty watches in 80% of the time Alice watches. So:

$P = 0.6*0.8 = 0.48$

There is a 48% probability that both Alice and Betty watch TV tomorrow.

b) What is the probability that Betty watches TV tomorrow?

Since Betty only watches when Alice watches(80% of the time), this probability is the same as the probability of both of them watching. So

$P = 0.6*0.8 = 0.48$

There is a 48% probability that Betty watches TV tomorrow.

c) What is the probability that only Alice watches TV tomorrow?

There is a 60% probability that Alice watches TV tomorrow. If she watches, there is an 80% probability that Betty watches and a 20% probability she does not watch.

$P = 0.6*0.2 = 0.12$

There is a 12% probability that only Alice watches TV tomorrow.

7 0

3 years ago