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gizmo_the_mogwai [7]
3 years ago
11

Look at each equation and possible solution. Is the solution correct? Select Yes or No for each equation.

Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
7 0

Answer:

yes

Step-by-step explanation:

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If you throw 3 dice, the probability of getting 3 sixes is 0.5%. The probability of getting no sixes is 57.9%. Find the probabil
PtichkaEL [24]

Answer:

A) 99.5%

B) 42.1%

Step-by-step explanation:

A) Since the probability of 3 sixes is 0.5%, the probability of less than 3 sixes (that is, zero, one, or two sixes) is 100% - 0.5%, or 99.5%

B ) Since the probability of no sixes is 57.9%, the probability of at least 1 six is 100% - 57.9%, or 42.1%

7 0
2 years ago
A ball is thrown upward from the top of a building. The function below shows the height of the ball in relation to sea level, f(
Verizon [17]
For this case we have the following function:
 f (t) = -16t2 + 48t + 100
 The average rate of change is:
 (f (t2) - f (t1)) / (t2 - t1)
 We have then:
 For t1 = 3:
 f (3) = -16 * (3) ^ 2 + 48 * (3) + 100
 f (3) = 100
 For t2 = 5:
 f (5) = -16 * (5) ^ 2 + 48 * (5) + 100
 f (5) = -60
 Substituting values:
 AVR = (-60 - 100) / (5 - 3)
 AVR = -80
 Answer:
 
The average rate of change of f (t) from t = 3 seconds to t = 5 seconds is -80 feet per second.
8 0
4 years ago
Involving the selection of frozen dinners. Assume that there are 15 frozen dinners: 7 pasta, 6 chicken, and 2 seafood dinners. T
zzz [600]

The probability that at least 2 of the dinners selected are pasta dinners will be 0.8181...

<u><em>Explanation</em></u>

Pasta dinners = 7 , Chicken dinners = 6 and Seafood dinners = 2  

The student selects 5 of the total 15 dinners. So, total possible ways for selecting 5 dinners =^1^5C_{5} =3003

For selecting at least 2 of them as pasta dinners, the student can select 2, 3, 4 and 5 pasta dinners from total 7 pasta dinners.

So, the possible ways for selecting 2 pasta dinners =^7C_{2}*^8C_{3} =1176

The possible ways for selecting 3 pasta dinners =^7C_{3}*^8C_{2} =980

The possible ways for selecting 4 pasta dinners =^7C_{4}*^8C_{1} =280

The possible ways for selecting 5 pasta dinners =^7C_{5}*^8C_{0} =21

Thus, the probability for selecting at least 2 pasta dinners =\frac{1176+980+280+21}{3003} =\frac{2457}{3003} =0.8181.....

3 0
4 years ago
Two numbers x and y, have a sum of 23 and a difference of 7. x is greater than y.
Finger [1]

Answer:

X+Y =23

X-Y =7

Is this the answer you were looking for??

5 0
3 years ago
Solve for x: -6 &lt; x - 1 &lt; 9
Shkiper50 [21]

Answer:

x = (-5,10)

Step-by-step explanation:

4 0
3 years ago
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