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3 years ago

Find the value of each variable. Round your answers to the nearest tenth. (Soh Coh Toa)

Mathematics

2 answers:

kiruha [24]3 years ago

6 0

Answer:

k = 10 tan (40) = 8.39 (to 2 decimals)

J = 10 / cos(40) = 13.05 (to 2 decimals)

Step-by-step explanation:

It is SOH CAH TOA, or

Sin = Opposite / Hypotenuse

Cos = Adjacent / Hypotenuse

Tan = Opposite / Adjacent

Using SOH CAH TOA,

tan(40) = k/10, so k = 10 tan (40) = 8.39 (to 2 decimals)

cos(40) = 10 / j, so J = 10 / cos(40) = 13.05 (to 2 decimals)

Butoxors [25]3 years ago

3 0

Answer:

k = 8.4, j = 13.1

Step-by-step explanation:

Solve for k:

$tan(40)=\frac{k}{10}\\10(tan(40))=k\\8.4=k$

Solve for j:

$8.4^2+10^2=j^2\\70.56+100=j^2\\170.56=j^2\\13.1=j$

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spin [16.1K]

The other endpoint is (1, -17).

The midpoint formula is:

$m=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$

Using our midpoint and endpoint, we have:
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\\
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For the first equation (to find the x-coordinate) we will multiply both sides by 2:
$6\times2=\frac{11+x_2}{2}\times 2
\\
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Subtract 11 from both sides:
12 - 11 = 11+x₂ - 11
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For the second equation (the y-coordinate) we multiply both sides by 2:
$-11\times2=\frac{-5+y_2}{2}\times 2
\\
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Add 5 to both sides:
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This means that (x₂, y₂) is at (1, -17).

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3 years ago

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Setler [38]

Answer:

Step-by-step explanation:

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3 years ago

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ddd [48]

Distribute ^4 to both 2 and q^5

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(q^5)^4 = q^20

16(q^20) = 16q^20

16q^20 is your answer

hope this helps

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Answer:

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