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2 years ago

9

There are 2 blue, 3 green and 10 red marbles in a bag. What is the Probability of pulling a red marble, replacing it, then pulli

ng a blue marble?

1 answer:

Kamila [148]2 years ago

3 0

Answer:

i think its this.. ._.

Step-by-step explanation:

if red is 10, and pulling a blue is 2, there is a 10/15 chace you will get a red, but a 2 out of 15 chance you will get a blue

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Someone help and plz make sure it’s right :)

fenix001 [56]

The value of the trigonometric ratio, Cos C is 5/13. The answer is A.

3 0

2 years ago

According to the National Bridge Inspection Standard (NBIS), public bridges over 20 feet in length must be inspected and rated e

slamgirl [31]

Answer:

1.80% probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

Step-by-step explanation:

For each bridge, there are only two possible outcomes. Either it has rating of 4 or below, or it does not. The probability of a bridge being rated 4 or below is independent from other bridges. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

For the year 2020, the engineers forecast that 9% of all major Denver bridges will have ratings of 4 or below.

This means that $p = 0.09$

Use the forecast to find the probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

Either less than 4 have a rating of 4 or below, or at least 4 does. The sum of the probabilities of these events is 1.

So

$P(X < 4) + P(X \geq 4) = 1$

We want $P(X \geq 4)$

So

$P(X \geq 4) = 1 - P(X < 4)$

In which

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{12,0}.(0.09)^{0}.(0.91)^{12} = 0.3225$

$P(X = 1) = C_{12,1}.(0.09)^{1}.(0.91)^{11} = 0.3827$

$P(X = 2) = C_{12,2}.(0.09)^{2}.(0.91)^{10} = 0.2082$

$P(X = 3) = C_{12,3}.(0.09)^{3}.(0.91)^{9} = 0.0686$

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.3225 + 0.3827 + 0.2082 + 0.0686 = 0.982$

Finally

$P(X \geq 4) = 1 - P(X < 4) = 1 - 0.982 = 0.0180$

1.80% probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

6 0

2 years ago

Plz show working for binary addition. please solve. 11000 + 110101 + 101011

olga_2 [115]

Answer: The answer to this is 222112

Step-by-step explanation: Its quite simple actually, you add all these numbers together, you bring up any ones that are extras then you add all the ones to the direct answer :> ( Hope this helps!)

4 0

2 years ago

Consider the following functions. f={(−4,−1),(1,1),(−3,−2),(−5,2)} and g={(1,1),(2,−3),(3,−1)}: Find (f−g)(1).

fenix001 [56]

Answer:

0

Step-by-step explanation:

Subtraction of functions has the property:

(f−g)(1) = f(1) - g(1)

f={(−4,−1),(1,1),(−3,−2),(−5,2)} has (1,1) means that f maps 1 to 1, therefore f(1) = 1

g={(1,1),(2,−3),(3,−1)} has (1,1), means that g maps 1 to 1, therefore g(1)=1

As a Result, since (f−g)(1) = f(1) - g(1), we have (f−g)(1) = 1-1=0

7 0

2 years ago

The Chickens and Pigs Problem A farmer saw some chickens and pigs in a field. He counted 15 heads and 44 legs. Problem solve to

Flauer [41]

Answer:

15 pigs 22 chickens

Step-by-step explanation:

So if there are 15 heads, that means there 15 pigs and we know chickens have 2 legs, so we do do 44/2 = 22, so there are 15 pigs and 22 chickens

6 0

3 years ago