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KiRa [710]
3 years ago
9

Identify the inverse g(x) of the given relation f(x).

Mathematics
2 answers:
Leviafan [203]3 years ago
5 0

The first answer is ...


D. g(x) = {(3, 8), (1, 4), (–1, 0), (–3, –4)}


And the second answer is ...


C. g(x) is a function because f(x) is one-to-one.

sveta [45]3 years ago
3 0
1)the last one 2) g(x) is function beacause fx is one - to-one
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Step-by-step explanation:

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Which of the following prove that (-3) + 5 = 2? Select all that apply.
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D

Step-by-step explanation:

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What is the following product
dangina [55]

Option B is correct.

Step-by-step explanation:

We need to solve: \sqrt[3]{x^2}\sqrt[4]{x^3}

We know that: \sqrt[n]{x}\sqrt[b]{x} =\sqrt[n*b]{x.x}= \sqrt[n*b]{x^2}

Applying the above rule:

\sqrt[3]{x^2}\sqrt[4]{x^3}\\=\sqrt[3*4]{x^2.x^3}\\=\sqrt[12]{x^5}

So, Option B is correct.

Keywords: Solving with Exponents

Learn more about Solving with Exponents at:

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3 years ago
Complete the point-slope equation of the line through (2,3 and (7,4). Use exact numbers.
uysha [10]

The point-slope equation of the line is y-3=\frac{1}{5}(x-2)

Step-by-step explanation:

The form of the point-slope equation is y-y_{1}=m(x-x_{1}) , where

  • m is the lope of the line
  • (x_{1},y_{1}) is a point lies on the line

The slope of a line m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} , where

(x_{1},y_{1}) and (x_{2},y_{2}) are two points on the line

∵ The line through (2 , 3) and (7 , 4)

∴ x_{1} = 2 and x_{2} = 7

∴ y_{1} = 3 and y_{2} = 4

- Substitute these value in the rule of the slope

∵ m=\frac{4-3}{7-2}=\frac{1}{5}

∴ the slope of the line is m=\frac{1}{5}

Let us substitute the value of the slope and the coordinates of point (x_{1},y_{1}) in the form of the equation

∵ y-y_{1}=m(x-x_{1})

∵ x_{1} = 2 and y_{1} = 3

∵ m=\frac{1}{5}

∴ y-3=\frac{1}{5}(x-2)

The point-slope equation of the line is y-3=\frac{1}{5}(x-2)

Learn more:

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