Since y=3x+15
sub 3x+15 for y in other equation
2x+3(3x+15)=1
2x+9x+45=1
minus 45
11x=-44
divide 11
x=-4
sub
y=3x+15
y=3(-4)+15
y=-12+15
y=3
(-4,3)
Answer:
The answer to your question is the first option
Step-by-step explanation:
64
Process
1.- Find the prime factors of 64
64 2
32 2
16 2
8 2
4 2
2 2
1
64 = 2⁶
2.- Express 64 as a fractional exponent
64
3.- Simplify
64
64
64![^{1/4} = 2\sqrt[4]{2^{2}}](https://tex.z-dn.net/?f=%5E%7B1%2F4%7D%20%3D%202%5Csqrt%5B4%5D%7B2%5E%7B2%7D%7D)
4.- Result
64![^{1/4} = 2\sqrt[4]{4}](https://tex.z-dn.net/?f=%5E%7B1%2F4%7D%20%3D%202%5Csqrt%5B4%5D%7B4%7D)
Answer:
-25.49
Step-by-step explanation:
(-3.8)+(-21.14)+(-0.55)
-3.8-21.14-0.55
-25.49
Answer:
a. 5177 cm³
b. 3,451 cm³
c. 67%
Step-by-step explanation:
Given:
Diameter of each ball (d) = 13 cm
Radius of the ball (r) = radius of the cylinder = ½(13) = 6.5 cm
Height of the cylinder (h) = the sum of the diameters of the 3 balls = 3(13) = 39 cm
a. Volume of cylinder = πr²h
Plug in the values
Volume of cylinder = π*6.5²*39 = 5176.56 ≈ 5177 cm³
b. Total volume of the three balls = 3(volume of 1 ball) = 3(volume of sphere) = 3(⁴/3πr³)
Plug in the value
Total volume of the 3 balls = 3(⁴/3*π*6.5³) = 3(1150.35) = 3,451.05 ≈ 3,451 cm³
c. % of volume of the container occupied by the 3 balls = total volume of the three balls / volume of cylinder × 100
Plug in the values
= 3,451/5177 × 100
= 66.6602279
≈ 67%
