Answer:
Step-by-step explanation:
Letting "a" and "c" represent the costs of adult tickets and child tickets, the problem statement gives us two relations:
3a +5c = 52
2a +4c = 38
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We can solve this system of equations using "elimination" as follows:
Dividing the first equation by 2 we get
a +2c = 19
Multiplying this by 3 and subtracting the first equation eliminates the "a" variable and tells us the price of a child ticket:
3(a +2c) -(3a +4c) = 3(19) -(52)
c = 5 . . . . . . collect terms
a +2·5 = 19 . . substitute for c in the 3rd equation above
a = 9 . . . . . . subtract 10
One adult ticket costs $9; one child ticket costs $5.
Convert 3 6/2 to an improper fraction so: 12/2
convert 2 4/5 to 14/5
multiply the numerators of the improper fractions so 12*14, which is 168.
multiple the denominators so 2*5, which is 10.
the new fraction is 168/10, so you divide 168 divided by 10, which is 16.8, or 16 4/5.
There is no possible answer.
The #s are 420, 480, and 540.
None of them are 40 away from a multiple of 100.
However, it is was between 300 and 600, the answer would be 360.
Answer:
Parent function: 
Step-by-step explanation:
Parent function is the simplest form of the type of function given
for equation: 
the simplest form is:
Answer:
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Step-by-step explanation:
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