Using the knowledge in computational language in python it is possible to write a code that computes an integer's checksum.
<h3>Writting the code:</h3>
<em>def checkSum(n):                    # Function definition</em>
<em>    total = 0                       # total variable which returns sum</em>
<em>    c = 0                           # counter variable which count the even position</em>
<em>    while(n!=0):                    # running a loop while n != 0</em>
<em>        r = int(n%10)               #breaking the number into digits</em>
<em>        c=c+1                       # increase counter</em>
<em>        if c%2==0:                  # if counter is even position then double the number </em>
<em>            r = r*2</em>
<em>            while(r!=0):                            # do the process</em>
<em>                total = total + int(r%10)</em>
<em>                r = int(r/10)</em>
<em>            n=int(n/10)    </em>
<em>        else:                       # if counter is odd position then simple add the digit </em>
<em>            total = total + r       # into total</em>
<em>            n=int(n/10)</em>
<em>    return total                    # in the last return the sum of digits</em>
<em># Driver code</em>
<em>n = int(input("Enter Number:"))         # asking user to enter the number </em>
<em>print(checkSum(n))                      # calling the function</em>
See more about python at brainly.com/question/18502436
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