1/5 is .2
.1^2 is .01
.02 is .02
So the furthest left would be the smallest number, which in this case is 0.1^2
Answer:
![(x-2)(8x+4)](https://tex.z-dn.net/?f=%28x-2%29%288x%2B4%29)
Step-by-step explanation:
we have
![8x^{2} -12x-8](https://tex.z-dn.net/?f=8x%5E%7B2%7D%20-12x-8)
Equate to zero and find the roots of the quadratic equation
The formula to solve a quadratic equation of the form
is equal to
![x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%28%2B%2F-%29%5Csqrt%7Bb%5E%7B2%7D-4ac%7D%7D%20%7B2a%7D)
in this problem we have
![8x^{2} -12x-8=0](https://tex.z-dn.net/?f=8x%5E%7B2%7D%20-12x-8%3D0)
so
![a=8\\b=-12\\c=-8](https://tex.z-dn.net/?f=a%3D8%5C%5Cb%3D-12%5C%5Cc%3D-8)
substitute in the formula
![x=\frac{-(-12)(+/-)\sqrt{-12^{2}-4(8)(-8)}} {2(8)}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-%28-12%29%28%2B%2F-%29%5Csqrt%7B-12%5E%7B2%7D-4%288%29%28-8%29%7D%7D%20%7B2%288%29%7D)
![x=\frac{12(+/-)\sqrt{400}} {16}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B12%28%2B%2F-%29%5Csqrt%7B400%7D%7D%20%7B16%7D)
![x=\frac{12(+/-)20} {16}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B12%28%2B%2F-%2920%7D%20%7B16%7D)
![x_1=\frac{12(+)20} {16}=2](https://tex.z-dn.net/?f=x_1%3D%5Cfrac%7B12%28%2B%2920%7D%20%7B16%7D%3D2)
![x_2=\frac{12(-)20} {16}=-\frac{1}{2}](https://tex.z-dn.net/?f=x_2%3D%5Cfrac%7B12%28-%2920%7D%20%7B16%7D%3D-%5Cfrac%7B1%7D%7B2%7D)
therefore
![8x^{2} -12x-8=8(x-2)(x+\frac{1}{2})=(x-2)(8x+4)](https://tex.z-dn.net/?f=8x%5E%7B2%7D%20-12x-8%3D8%28x-2%29%28x%2B%5Cfrac%7B1%7D%7B2%7D%29%3D%28x-2%29%288x%2B4%29)
Thank lord for you please thank you lord lord please thank you please thank you lord please
Answer:
324 units
Step-by-step explanation:
First find the measurements of the square.
24 ÷ 4 = 6
Each side of the square is 6 units.
Now scale by 3
6 × 3 = 18
Each side of the square is now 18 units
Find the area:
18 × 18 = 324
Answer:
I think so, but don't lose sight