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Goshia [24]
3 years ago
14

Write the following algebraically, using x as your

Mathematics
1 answer:
bogdanovich [222]3 years ago
4 0

Answer:

(X - 1)3

Step-by-step explanation:

I’m not so sure but this is the best I can do. If this helps, pls give brainliest.

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Jermiah works at an appliance store. He reacantly sold 12 clothes dryers and 36 other appliances. Of the next 100 appliances he
Viefleur [7K]
12/36 = x/100
Then cross multiply
1200 = 36x
Divide by 36
x = 33.33

Can’t sell 0.33 of an appliance, so your answer is 33.
4 0
2 years ago
200 meters
Katyanochek1 [597]

Answer:

520 m

Step-by-step explanation:

Perimeter is the distance around a shape. To find the perimeter, you add up all the sides.

200 + 60 + 60 + 200 = 520 m

7 0
2 years ago
Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive
LenaWriter [7]

Answer:

(a) The probability that all the next three vehicles inspected pass the inspection is 0.343.

(b) The probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c) The probability that exactly 1 of the next three vehicles passes is 0.189.

(d) The probability that at most 1 of the next three vehicles passes is 0.216.

(e) The probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

Step-by-step explanation:

Let <em>X</em> = number of vehicles that pass the inspection.

The probability of the random variable <em>X</em> is <em>P (X) = 0.70</em>.

(a)

Compute the probability that all the next three vehicles inspected pass the inspection as follows:

P (All 3 vehicles pass) = [P (X)]³

                                    =(0.70)^{3}\\=0.343

Thus, the probability that all the next three vehicles inspected pass the inspection is 0.343.

(b)

Compute the probability that at least 1 of the next three vehicles inspected fail as follows:

P (At least 1 of 3 fails) = 1 - P (All 3 vehicles pass)

                                   =1-0.343\\=0.657

Thus, the probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c)

Compute the probability that exactly 1 of the next three vehicles passes as follows:

P (Exactly one) = P (1st vehicle or 2nd vehicle or 3 vehicle)

                         = P (Only 1st vehicle passes) + P (Only 2nd vehicle passes)

                              + P (Only 3rd vehicle passes)

                       =(0.70\times0.30\times0.30) + (0.30\times0.70\times0.30)+(0.30\times0.30\times0.70)\\=0.189

Thus, the probability that exactly 1 of the next three vehicles passes is 0.189.

(d)

Compute the probability that at most 1 of the next three vehicles passes as follows:

P (At most 1 vehicle passes) = P (Exactly 1 vehicles passes)

                                                       + P (0 vehicles passes)

                                              =0.189+(0.30\times0.30\times0.30)\\=0.216

Thus, the probability that at most 1 of the next three vehicles passes is 0.216.

(e)

Let <em>X</em> = all 3 vehicle passes and <em>Y</em> = at least 1 vehicle passes.

Compute the conditional probability that all 3 vehicle passes given that at least 1 vehicle passes as follows:

P(X|Y)=\frac{P(X\cap Y)}{P(Y)} =\frac{P(X)}{P(Y)} =\frac{(0.70)^{3}}{[1-(0.30)^{3}]} =0.3525

Thus, the probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

7 0
2 years ago
Plz help me NOW I will mark you brainliest
puteri [66]
  • Let x be the percentage of p.
  • Therefore,
  • m\% \:  \: of \:  \: n = x\% \:  \: of \:  \: p \\  =  >  \frac{mn}{100}  =  \frac{px}{100}  \\  =  > mn =  \frac{px}{100}  \times 100 \\  =  > mn = px \\  =  >  \frac{mn}{p}  = x

<u>Answer:</u>

<u>\frac{mn}{p}</u>

Hope you could get an idea from here.

Doubt clarification - use comment section.

8 0
2 years ago
Yu narukami fight me rigth now⇆⇆π⇒ωω↑ω⊇→→∧∉⇔⇒ππ∠⇄㏑∡⇄⇆→←βαβ∀∀⊅⊄ФФω≅
Andru [333]
Nani!? Omae wa mou shindeiru
3 0
2 years ago
Read 2 more answers
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