the number of elements in the union of the A sets is:5(30)−rAwhere r is the number of repeats.Likewise the number of elements in the B sets is:3n−rB
Each element in the union (in S) is repeated 10 times in A, which means if x was the real number of elements in A (not counting repeats) then 9 out of those 10 should be thrown away, or 9x. Likewise on the B side, 8x of those elements should be thrown away. so now we have:150−9x=3n−8x⟺150−x=3n⟺50−x3=n
Now, to figure out what x is, we need to use the fact that the union of a group of sets contains every member of each set. if every element in S is repeated 10 times, that means every element in the union of the A's is repeated 10 times. This means that:150 /10=15is the number of elements in the the A's without repeats counted (same for the Bs as well).So now we have:50−15 /3=n⟺n=45
To get the answer we can use proportion
8 ginger ----------------- 3 fruit
12 ginger ----------------x
Crossmultiply now
8x=12*3 /:8
x=
x=<u />
To not change ratio we have to have 4.5 cups of fruilt juice. We initialy had 3, so we have to add 1.5 cup of fruit juice.
Answer:
First, keep the first number, Second, change the operation from subtraction to addition, Next, get the opposite sign of the second number (known as the subtrahend) and Lastly, proceed with the regular addition of integers.
Step-by-step explanation:
Find common denominators. 10 is the common denominator. Multiply 2 to numerator and denominator of -3/5
(-3/5)(2/2) = -6/10
x + 1/10 = -6/10
Isolate the x. Subtract 1/10 from both sides
x + 1/10 (-1/10) = -6/10 (-1/10)
x = -6/10 - 1/10
x = -7/10
-7/10 is your answer for x
hope this helps
