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rjkz [21]
3 years ago
7

Which of the following statements is false? (5 points)

Mathematics
1 answer:
goldenfox [79]3 years ago
7 0
I really think it is a
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a teacher promised a movie day to the class that did better, on average, on their test. The box plot shows the results of the te
natka813 [3]

The question is incomplete. The complete question is

A teacher promised a movie day to the class that did better, on average, on their test. The box plot shown in the below-mentioned figure shows the results of the test.

Which class should get the reward, and why?

- The 2nd-period class should get the reward. They have the highest score, a perfect 100.

- The 2nd-period class should get the reward. They have a higher median.

- The 4th-period class should get the reward. Though the medians are the same, the first and third quartiles are higher, so the students did better on average than in the 2nd-period class.

- The 4th-period class should get the reward. Their lowest score is an outlier and should be thrown out.

The box plot shown in the question provides the information that
In 2nd period the minimum of the data is 77, first quartile is 78, median of the data is 89, third quartile is 92 and the maximum of the data is 100.
Hence, the mean of the results of 2nd period is

\frac{77+78+89+92+100}{5}=87.2

In 2nd period the minimum of the data is 72, first quartile is 83, median of the data is 89, third quartile is 96 and the maximum of the data is 98.

Hence, the mean of the results of the 4th period is

\frac{72+83+89+96+98}{5}=87.6

Hence, obviously, the 4th period is having more mean.

Moreover, we can observe that if more of the marks are on the higher side the average will automatically be more. Hence, as the first and the third quartiles are more on the 4th-period, so the average marks for the 4th period must be better.

So, just by observing the box plot, we can give the statement that  "The 4th-period class should get the reward. Though the medians are the same, the first and third quartiles are higher, so the students did better on average than in the 2nd-period class. "

Therefore, the 4th-period class should get the reward. Though the medians are the same, the first and third quartiles are higher, so the students did better on average than in the 2nd-period class.

Learn more about box plots here-

brainly.com/question/1523909

#SPJ10

6 0
1 year ago
Solve for x.<br><br> 3(3x - 1) + 2(3 - x) = 0
olganol [36]
Use distributive property to get rid of the parenthesis.....

9x - 3 + 6 - 2x = 0
combine like terms
7x + 3 = 0
move the 3 over by subtraction
7x = -3
divide by 7
x = -3/7
7 0
3 years ago
Read 2 more answers
I need help I would really thank whoever answers this for me
Mars2501 [29]
To do these problems, you plug in the ‘n’ value given into the equation.

a. 6j - 3 : j = 4
6(4) - 3
24 - 3
21

b. 1/2b + 5 : b = 14
1/2(14) + 5
7 + 5
12

c. 8 + 4k : k = 3.5
8 + 4(3.5)
8 + 14
22
6 0
3 years ago
Read 2 more answers
Which of the following functions is graphed below?
kompoz [17]

Answer:

A

Step-by-step explanation:

vertex is (-3,-4)

so inside the absolute value bars need to be postive 3 and the four has to be -4.

6 0
3 years ago
Calculate the diameter of the circle
lianna [129]

Answer:

2.64cm

Step-by-step explanation:

A = π r^2

5.5 = π r^2

1.75 = r^2

r = 1.32

Diameter is then 2(1.32) = 2.64

3 0
3 years ago
Read 2 more answers
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