Answer:
B. 4% on a weekly wage of 280.
Step-by-step explanation:
You will be getting paid faster, which is giving you more cash. I hope I got this right, goodluck bro!
Try -×=4??? i just started to learn how to do variable expressions correctly bc i just transfered to an high accelerating school, but if I'm wrong w the answer im very sorry, as i am just now learning.
The Percentage of Sally's Team Wins :
Given : Total Number of Games the Team Played = 25
Given : Number of Games won by the Team = 17
⇒ The Percentage of Sally's Team Wins = (17 × 4) = 68%
The probability of selecting exactly one ace is its likelihood
The probability that a five-card poker hand contains exactly one ace is 29.95%
<h3>How to determine the probability?</h3>
There are 4 aces in a standard deck of 52 cards.
The probability of selecting an ace would be:
p = 4/52
Also, there are 48 non-ace cards in the standard deck
So, the probability of selecting a non-ace after an ace has been selected is:
p = 48/51
The probability of selecting a non-ace up to the fifth selection are:
- After two cards have been selected is: 47/50.
- After three cards have been selected is: 46/49.
- After four cards have been selected is: 45/48.
The required probability is then calculated as:
P(1 Ace) = n * (4/52) * (48/51) * (47/50) * (46/49) * (45/48)
Where n is the number of cards i.e. 5
So, we have:
P(1 Ace) = 5 * (4/52) * (48/51) * (47/50) * (46/49) * (45/48)
Evaluate
P(1 Ace) = 0.2995
Express as percentage
P(1 Ace) = 29.95%
Hence, the probability that a five-card poker hand contains exactly one ace is 29.95%
Read more about probability at:
brainly.com/question/25870256
X = 1 / 4
1 / 4 + 1 / 2 = 0.75 = 3/4
