I think you might be referring to the definite integral,
Recall the definition of absolute value:
Then 
if 
, and 
is 
. So spliting up the integral at <em>x</em> = 1, we have
The rest is simple:
Answer:
This is always ''interesting'' If you see an absolute value, you always need to deal with when it is zero:
(x-4)=0 ===> x=4,
so that now you have to plot 2 functions!
For x<= 4: what's inside the absolute value (x-4) is negative, right?, then let's make it +, by multiplying by -1:
|x-4| = -(x-4)=4-x
Then:
for x<=4, y = -x+4-7 = -x-3
for x=>4, (x-4) is positive, so no changes:
y= x-4-7 = x-11,
Now plot both lines. Pick up some x that are 4 or less, for y = -x-3, and some points that are 4 or greater, for y=x-11
In fact, only two points are necessary to draw a line, right? So if you want to go full speed, choose:
x=4 and x= 3 for y=-x-3
And just x=5 for y=x-11
The reason is that the absolute value is continuous, so x=4 works for both:
x=4===> y=-4-3 = -7
x==4 ====> y = 4-11=-7!
abs() usually have a cusp int he point where it is =0
Step-by-step explanation:
we are given points as
(-2,-4)
(0,2)
(1,5)
we can points
and then we can join them
After that we can get idea about it's shape
we can see that
this is straight line
so, this is linear model
Hence, option-C................Answer
Answer:
r=15.99
Step-by-step explanation:
r=C
2π=100.48
2·π≈15.99189
