4 unit squares each have 4/5 of their area shaded what is the total of that area shaded
1 answer:
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One way is to factor and group and get every 3
729=3 times 3 times 3 times 3 times 3 times 3
so we group the ones that happen 3 times
729=(3*3*3) times (3*3*3)
we know that we can take the cube root of each group and multiply the result
729=![( \sqrt[3]{3*3*3})( \sqrt[3]{3*3*3})](https://tex.z-dn.net/?f=%28%20%5Csqrt%5B3%5D%7B3%2A3%2A3%7D%29%28%20%5Csqrt%5B3%5D%7B3%2A3%2A3%7D%29)
=(3)(3)=9
the answer is 9
729=3 times 3 times 3 times 3 times 3 times 3
so we group the ones that happen 3 times
729=(3*3*3) times (3*3*3)
we know that we can take the cube root of each group and multiply the result
729=
the answer is 9
Answer:
- 61x - 67
Step-by-step explanation:
The n th term of an arithmetic sequence is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
d = - 9x - 2 - (- 5x + 3)
= - 9x - 2 + 5x - 3
= - 4x - 5 and a₁ = - 5x + 3, thus
= - 5x + 3 + 14(- 4x - 5) = - 5x + 3 - 56x - 70 = - 61x - 67