Can somebody help me?

IgorLugansk [536]

I hope this helps you

244=4.61

2square roof 61

7 0

4 years ago

In the year 2019, Lee County used approximately 55 million gallons of water. Historical trends show that each year the water dem

Harlamova29_29 [7]

Answer:

Approximately 62 gallons of water will be used by Lee County by the year 2025.

Step-by-step explanation:

The amount, in millions gallons of water, spent by Lee County, in t years after 2019, is given by the following equation:

$P(t) = P(0)(1 + r)^{t}$

In which P(0) is the amount spent on 2019 and r is the increse rate, as a decimal.

In the year 2019, Lee County used approximately 55 million gallons of water.

This means that $P(0) = 55$

Historical trends show that each year the water demand is increasing by a rate of approximately 2.1%.

This means that $r = 0.021$

So

$P(t) = P(0)(1 + r)^{t}$

$P(t) = 55(1 + 0.021)^{t}$

$P(t) = 55(1.021)^{t}$

Approximately how many million gallons of water will be used by Lee County by the year 2025?

2025 is 2025 - 2019 = 6 years after 2019. So this is P(6).

$P(t) = 55(1.021)^{t}$

$P(6) = 55(1.021)^{6}$

$P(6) = 62.3$

Rounded to the nearest millions

Approximately 62 gallons of water will be used by Lee County by the year 2025.

3 0

4 years ago

How do u make this 4/4?

Oksana_A [137]

well, if look at the timetable, She got the 08:30am train from Aberystwyth and arrives on time at Shrewsbury, from the timetable we know she arrived at 10:17am, now she did some rigamarole and got back to the Train station at Shrewsbury 4 hours later. Well, we know she arrived at 10:17am, if we add 4 hours to that that'll make it 1417 or namely 2:17pm.

well, the Train arrives at Shrewsbury a 14 19, or 2:19pm, she is there at 2:17pm, so she's really 2 minutes before the Train arrives at Shrewsbury, she's right on time, possibly with some munchies too.

14 19 > 14 17.

8 0

3 years ago

Which letter is the correct answer and why

Julli [10]

Answer:

<h2>Option C</h2>

Step-by-step explanation:

Here,

[Taking 'A' = 'a']

$a \: = \: 4\pi {r}^{2}$