<h3>To find the product of 42.12 and 10^3, move the decimal point in 42.12 3 places to the right because 10^3 has 3 zeros</h3>
<em><u>Solution:</u></em>
Given that,

Which means,

Here, the exponent of 10 is positive ( which is 3)
When the exponent is positive, we have to move the decimal point to right
When you multiply a number by a power of 10, ( 10!, 10^2, and so on ) move the decimal point of the number to the right the same number of places as the number of zeros in the power of 10
Here, exponent is 3 , therefore move the decimal point right 3 places in 42.12
Therefore,

Answer:
x=2, y=3
Step-by-step explanation:
First, graph both equations on a rectangular coordinate system (see attached screenshot). Then, simply figure out where these two lines intersect. Since they intersect at (2,3), x=2 and y=3.
Plugging these values in the equations for x and y, you can see if these are the correct answers:
(3)=3(2)-3, (2)+(3)=5
Since both of these are true, you have the right answer.
Hope this helps!
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Answer:


Step-by-step explanation:
a.
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b.
![[\because \int x^n dx=\dfrac{x^{n+1}}{n+1}+C]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Cint%20x%5En%20dx%3D%5Cdfrac%7Bx%5E%7Bn%2B1%7D%7D%7Bn%2B1%7D%2BC%5D)
c.
![[\because \dfrac{adx}{x\sqrt{x^2-a^2}}=\csc^{-1}(\dfrac{x}{a})+C]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Cdfrac%7Badx%7D%7Bx%5Csqrt%7Bx%5E2-a%5E2%7D%7D%3D%5Ccsc%5E%7B-1%7D%28%5Cdfrac%7Bx%7D%7Ba%7D%29%2BC%5D)