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2 years ago

PLEASEEEE HELP ME ILL GIVE YOU BRAINIEST!!

Mathematics

1 answer:

Jlenok [28]2 years ago

6 0

Answer:

48 in³

<h3> volume of triangular prism: Base Area * Height</h3>

Base Area:

$\hookrightarrow \sf \dfrac{1}{2} *base*height$

$\hookrightarrow \sf \dfrac{1}{2} *3*8$

$\hookrightarrow \sf 12 \ in^2$

Volume:

$\hookrightarrow \sf 12 * 4$

$\hookrightarrow \sf 48 \ in^3$

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Evaluate ab + 3c when a=-6, b=-2, and c=5

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Do it step by step
ab+3c
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A negative times a negative is positive. (-)(-)=+
12+3(5)
12+15
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4 years ago

If a and b are integers such that a2 − b2 = 100, what is the greatest possible value of a?

tatyana61 [14]

Answer:

Step-by-step explanation:

Question says that 'a' and 'b' are integers that implies we cannot have 'a' and 'b' in the form of decimals.

Now, lets expand the given equation:

$a^2-b^2=100$

$(a+b)(a-b)=100$

Lets say: $(a+b)=p$ , $(a-b)=q$

Let us consider the factor pairs of 100.

$(1 \times 100), (2 \times 50), (4 \times 25), (5 \times 20), (10 \times 10), (20 \times 5), (25 \times 4), (50 \times 2), (100 \times 1)$

Only factor pair $(2,50)$ gives us the integer values of 'a' and 'b'.

$a+b=50$ ....equation (1)

$a-b=2$ ........ equation (2)

adding equation 1 and 2, we get:

$2a=52$

$a=\frac{52}{2}=26$

$a-b=2$

Plugging the value of 'a' in the equation 2

$26-b=2$

$b=24$

So the greatest possible value of 'a' is 26.

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4 years ago

Choose the category of transformation related to the following statement:

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Answer:

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Step-by-step explanation:

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3 years ago

The following graph shows the amount of snow that fell in Denver, Colorado in the winter of 1888-1889. How many inches of snow d

podryga [215]

<h2>Hello!</h2>

The answer is:

The second option, Denver received 21.3 inches of snow during the period from 1888 to 1889.

To know how many inches of snow did Denver receive, we need to sum each the number of inches received per year from 1888 to 1889.

So, from the graph, we have:

For Nov '88, 3 inches.

For Dec '88, 0.8 inches.

For Jan '89, 5.5 inches.

For Feb '89, 8.4 inches.

For Mar '89, 3.6 inches.

Now, adding the number of inches for each month/year, we have:

$Total=3in+0.8in+5.5in+8.4in+3.6in=21.3inches$

Hence, we have that Denver received a total of 21.3 inches for the 1888-1889 year period.

Have a nice day!

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3 years ago