What is this called will give brainliest to the first person who answers thanks

I NEED HELP PLEASE!

jeyben [28]

9514 1404 393

Answer:

y = 1/4x + 5

Step-by-step explanation:

The given line has a "rise" of -8 for a "run" of 2, so a slope of ...

m = rise/run = -8/2 = -4

The perpendicular line will have a slope that is the opposite of the reciprocal of this slope. Its slope will be ...

-1/m = -1/(-4) = 1/4

The equation you're looking for will have an x-coefficient of 1/4. The suitable choice is ...

y = 1/4x + 5 . . . . the third choice

5 0

3 years ago

Assume that you have a sample of n 1 equals 6, with the sample mean Upper X overbar 1 equals 50, and a sample standard deviati

tigry1 [53]

Answer:

$t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656$

$df=6+5-2=9$

$p_v =P(t_{9}>2.656) =0.0131$

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

Step-by-step explanation:

Data given

$n_1 =6$ represent the sample size for group 1

$n_2 =5$ represent the sample size for group 2

$\bar X_1 =50$ represent the sample mean for the group 1

$\bar X_2 =38$ represent the sample mean for the group 2

$s_1=7$ represent the sample standard deviation for group 1

$s_2=8$ represent the sample standard deviation for group 2

System of hypothesis

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 \leq \mu_2$

Alternative hypothesis: $\mu_1 > \mu_2$

We are assuming that the population variances for each group are the same

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

The statistic for this case is given by:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

The pooled variance is:

$S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

We can find the pooled variance:

$S^2_p =\frac{(6-1)(7)^2 +(5 -1)(8)^2}{6 +5 -2}=55.67$

And the pooled deviation is:

$S_p=7.46$

The statistic is given by:

$t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656$

The degrees of freedom are given by:

$df=6+5-2=9$

The p value is given by:

$p_v =P(t_{9}>2.656) =0.0131$

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

4 0

3 years ago

If the radius of a circle is 75 hundredths of a meter, what is the diameter?

givi [52]

We know that the diameter of a circle is 2 times the radius.

If the radius is 0.75 meters, then the diameter must be 2 x 0.75 meters = 1.5meters

5 0

3 years ago

Can someone help me with this question please.

Daniel [21]

Answer:

c

Step-by-step explanation:

*View attached graph*

7 0

2 years ago

Can some one help me on this pls :(

Julli [10]

Answer:

Step-by-step explanation:

1= 2/3

2=5/6

3=21/40

4= 2 11/20

5= 1 1/3

6=5/6

7=1 1/2

8=9/10

9= 5 1/6

10= 2 1/2

6 0

3 years ago