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garik1379 [7]
3 years ago
13

The price of a item has dropped to $91 today. Yesterday it was $130. Find the percentage decrease.

Mathematics
1 answer:
Inga [223]3 years ago
6 0

That would be a 30% Decrease.

Here is how I found the answer:

Step 1: Find the difference between the two numbers by using this formula: Original Number - New number = Decrease.

Step 2: Divide the decrease by the original number and then multiply your answer by 100 by using this formula: Decrease / Original Number = % Decrease.

Now you can use these formulas to find any percentage decrease between two numbers.

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A bracelet costs $39.59 including tax.It is marked down 25 percent.What is the final price of the bracelet after it is marked do
lara31 [8.8K]
If it is marked down 25% and 25% equals 25/100 then you simply take 39.59 x 25/100

39.59 x 25/100 = 9.90

and then you subtract that from the original price 

39.59 - 9.90 = $29.69

after it is marked down, the price is $29.69
5 0
3 years ago
Read 2 more answers
Listed below are the weights in pounds of 11 players randomly selected from the roster of the Seattle Sea-hawks when they won Su
weeeeeb [17]

Answer:

No. These measures show a thinner team of NFL players according to the mean, variance, standard deviation, and quartiles.

Step-by-step explanation:

1) The measures of variation, namely The Range, Variance, Quartiles, Interquartiles, Sum of Squares, etc. shows us how the data are dispersed.

The Range Δ is calculated:

\Delta =305-189=116 Maximum value - Minimum value for weight

Mean:

\bar{x}=\frac{189+254+235+225+190+305+202+190+252+305}{11}\approx 231.09 \:pounds

Variance:

s^{2}=\frac{\sum_{i=1}^{n} (x_i-\bar{x})^{2}}{n-1}\Rightarrow s=1923.69\\

The Standard Deviation of the sample

s=\sqrt{s^{^{2}}}\Rightarrow s\approx 43.86\\

2) Since there is no preceding exercise, the comparison was made to a recent study in which a NFL player average weight is about 245 pounds (average),

Since 25% of this list are player whose weight is 192.5 lbs and 50% (2nd Quartile) =225 lbs , finally only at the 3rd Quartile we have players above the regular NFL average with 253. This, added with the other data, allow us to say that this list is not a typical of all NFL players.

4 0
3 years ago
The brand name of Mrs. Fields (cookies) has a 90% recognition rate. If Mrs. fields herself wants to verify that rate by beginnin
Schach [20]

Answer:

0.3874 = 38.74% probability that exactly 9 of the 10 consumers recognize her brand name.

0.6126 = 61.26% probability that the number who recognize her brand name is not nine.

Step-by-step explanation:

For each consumer, there are only two possible outcomes. Either they recognize the name, or they do not. The probability of a customer recognizing the name is independent of anu other customer. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The brand name of Mrs. Fields (cookies) has a 90% recognition rate.

This means that p = 0.9.

Sample of 10

This means that n = 10

Find the probability that exactly 9 of the 10 consumers recognize her brand name.

This is P(X = 9). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{10,9}.(0.9)^{9}.(0.1)^{1} = 0.3874

0.3874 = 38.74% probability that exactly 9 of the 10 consumers recognize her brand name.

Also, find the probability that the number who recognize her brand name is not nine.

1(100%) subtracted by those who recognize. So

1 - 0.3874 = 0.6126

0.6126 = 61.26% probability that the number who recognize her brand name is not nine.

4 0
3 years ago
Is (2,0) a solution to y<2x+4?
Tema [17]

Yes, (2,0) is a solution to y<2x+4

4 0
3 years ago
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wlad13 [49]
X= 3 to x = 4 has a greater rate of change
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3 years ago
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