A. it can be modified or rejected
I think it is electron. Electrons are located outside of the nucleus
Answer:
<span>GPE=81000J or 81kJ</span>
Explanation
Potential Energy = mgh = 20 x 9.8 x ?
<span>To find H use one of the equation of motion </span>
<span>= [(90)^2 - 0 ] / 2(9.8) </span>
<span>Potential Energy = mgh = 20 x 9.8 x 8100 /2(9.8) = 81000 J</span>
Answer:
2.124 kg of water
Explanation:
height of the falls is about 48 meters.
Mass of water needed is 1kg = 1000g
Power needed is 106 watts.
The amount of energy in 106 watts in one sec is 106 joules.
To calculate the energy of the 1kg falling water = Mgh
Energy = 1000*9.81*48
Energy = 470880 joules.
1 megawatt is = 1000000watts
The kilogram of water needed is 1000000/470880 = 2.124 kg of water
Answer:
Given: a projectile of initial launch velocity(V) and launch angle ∅ and no air resistance. At the maximum height, the projectile would have a zero contribution of speed from the vertical component(Vy) Therefore, if we say Vx=Vcos∅ is the only speed the projectile has at the instant of maximum height then we can replace Vx with 1/5V and write 1/5V=Vcos∅. Solving for the the launch angle ∅, gives Inverse Cos(1/5)=78.5 degrees.
