What frequency must a sound wave have in air to have the same wavelength as a 750 Hz sound wave in a platinum bar? Vair = 340 m/
1 answer:
Answer:
f = 91.1 Hz
Explanation:
As we know that it is given here that wavelength of sound in platinum is same as the wavelength of sound in air
so we can use the formula of wavelength in two mediums
now it is given that
frequency of sound in platinum is 750 Hz
now frequency of sound in air = f
now from above formula
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Explanation:
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- We can calculate this loss, applying Ohm's law to the internal resistance, as follows:
- The value of the potential difference between the terminals of the battery, is just the voltage of the battery, minus the loss in the internal resistance, as follows:
- We can solve for rint, as follows:
- When the circuit draws from battery a current I of 0.469A, we can find the potential difference between the terminals of the battery, as follows:
- As the current draw is larger, the loss in the internal resistance will be larger too, so the potential difference between the terminals of the battery will be lower.